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N76
18 hours ago
7

How many protons neutrons and electrons are there in a neutral atom of 43k (potassium-43)?

Chemistry
1 answer:
castortr0y [923]17 hours ago
3 0

Answer:

             Protons: 19

             Neutrons: 25

             Electrons: 19

Explanation:

Protons:

                   The atomic number determines the number of protons in an atom. Consequently, with Potassium's atomic number being 19, it contains 19 protons.

Neutrons:

                   The formula to find neutrons is:

                           # of Neutrons  =  Atomic Mass - # of Protons

Given:

                                Atomic Mass  =  43

                                # of Protons  =  19

Thus,

                                # of Neutrons  =  43 - 19

                                # of Neutrons  =  24

Electrons:

                                   In a neutral atom, the quantity of electrons matches that of protons. Therefore, a neutral Potassium atom with 19 protons must equally have 19 electrons.

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n the table below, write the density of each object. Then predict whether the object will float or sink in each of the fluids. W
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Answer:

0.5 g/mL----- will float

1.0 g/mL---- will float

2.0 g/mL----- will sink

Explanation:

Objects with a density less than or equal to that of water will float due to having a lower mass, while objects with a density exceeding that of water will sink because their mass is greater than that of water. Thus, objects with a density of 0.5 g/mL and 1.0 g/mL will float since they are less dense than water (1 g/mL), whereas an object with a density of 2.0 g/mL will sink.

3 0
11 days ago
The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan
eduard [944]

Response: The rate constant at 525 K is, 0.0606M^{-1}s^{-1}

Rationale:

Based on the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant when 701K = 2.57M^{-1}s^{-1}

K_2 = rate constant when 525K =?

Ea = activation energy for the process = 1.5\times 10^2kJ/mol=1.5\times 10^5J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 701 K

T_2 = final temperature = 525 K

Substituting the provided values into this formula yields:

\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]

K_2=0.0606M^{-1}s^{-1}

Thus, the rate constant at 525 K is, 0.0606M^{-1}s^{-1}

8 0
2 days ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
eduard [944]

Answer:- 64015 J

Solution: The calorimeter contains 4250 mL of water, which is at a temperature of 22.55 degrees Celsius.

The water's density is 1 gram per mL.

Thus, the mass of water = 4250mL(\frac{1g}{1mL}) = 4250 grams.

After introducing the hot copper bar, the final temperature of the water reaches 26.15 degrees Celsius.

Thus, \Delta T for the water = 26.15 - 22.55 = 3.60 degrees Celsius.

The specific heat capacity of water is 4.184 \frac{J}{g.^0C}.

To determine the heat absorbed by the water, we can use the following formula:

q=mc\Delta T

where q represents heat energy, m refers to mass, and c indicates specific heat.

Now let's substitute the values into the equation to perform the calculations:

q=4250g*\frac{4.184J}{g.^0C}*3.60^0C

q = 64015 J

Therefore, the water absorbs 64015 J of heat.



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When performing your experiment, you add your first drop of oleic acid/benzene solution, and a lens forms immediately. what is w
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