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Hitman42
1 month ago
15

Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.

Record in the appropriate blanks.

Chemistry
2 answers:
Alekssandra [2.9K]1 month ago
8 0

Answer: A= 0.5, B = 0.25, C = 0.125, D = 0.015625 and E = 0.00390625

Explanation:

The half-life of a substance refers to the duration it takes for that substance to decrease to half of its original quantity.

Here, n signifies the count of half-lives.

The remaining quantity of the substance after n half-lives can be determined using the formula provided, 0.5^{n}

When n = 1,

Fraction of substance remaining = 0.5¹ = 0.5.

This indicates that after the first half-life, the remaining quantity is half of the original amount.

Thus, we find A = 0.5

<pfor n="2," we="" calculate=""><pso after="" two="" half-lives="" the="" remaining="" quantity="" is="" of="" original=""><phence>B = 0.25 <pfor n="3," we="" have=""><pso after="" three="" half-lives="" the="" remaining="" amount="" is="" of="" original.=""><ptherefore we="" find="">C = 0.125<pfor n="6," we="" see="">

Thus, D = 0.015625

<pfor n="8," we="" calculate=""><pconsequently>E = 0.00390625

The calculated values for A, B, C, D, and E are 0.5, 0.25, 0.125, 0.015625, and 0.00390625 respectively.

</pconsequently></pfor></pfor></ptherefore></pso></pfor></phence></pso></pfor>
Anarel [2.7K]1 month ago
7 0
A=0.5
B=0.25
C=0.125
D=0.015625
E=0.00390625
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