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andrey2020
1 month ago
8

At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?

Chemistry
2 answers:
castortr0y [3K]1 month ago
8 0
To find the temperature at which the volume of the gas would be 0.550 L, given that it is 0.432 L at -20.0 °C, apply Charles’s Law.

The formula is v1/T1 = v2/T2
Known values:
V1 = 0.550 L
T1 = ?
T2 = -20°C + 273 = 253 K
V2 = 0.432 L

Rearranging for T1:
T1 = (V1 × T2) / V2

Calculating:
T1 = (0.55 L × 253) / 0.432 L = 322.11 K or 49.11°C
eduard [2.7K]1 month ago
4 0

Answer: 321.6 K

Explanation: The gas behavior follows Charles' Law, which states that at constant pressure and mass, volume is directly proportional to temperature.

V\propto T (assuming constant pressure and moles)

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where:

V_1 = initial volume = 0.432 L

V_2 = final volume = 0.550 L

T_1 = initial temperature = -20^oC=273-20=253K

T_2 = final temperature = unknown

Substituting known values into the formula yields final temperature:

\frac{0.432L}{253K}=\frac{0.550L}{T_2}

T_2=321.6K

Thus, the final temperature is 321.6 K.

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The atomic mass of 13C is 13.003355. Multiply the atomic mass of 13C by its abundance. Report the number to 8 significant digits
castortr0y [3046]

The result is 0.14303691.

Carbon-13 (¹³C) is a stable isotope of carbon with a mass number of 13, composed of six protons and seven neutrons.

Isotopes are elements that share the same atomic number but have different mass numbers, meaning they have a varying number of neutrons.

ω(¹³C) = 1.10% ÷ 100%.

ω(¹³C) = 0.0110; this indicates the natural abundance of carbon-13.

m(¹³C) = 13.003355; the atomic mass assigned to carbon-13.

ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.

ω(¹³C) · m(¹³C) = 0.14303691.

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Answer:

1) potential energy within the bond.

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6) Electrolysis

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lorasvet [2795]

Answer:

The original halide's formula is SrCl₂.

Explanation:

  • The chemistry reaction's balanced equation is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.

  • Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.
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  • The moles of SrX can thus be calculated as 4.11 x 10⁻³ moles based on stoichiometry from the balanced equation.
  • n = mass / molar mass, thus n =  4.11 x 10⁻³ moles and mass = 0.652 g.
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Answer: The correct option is (1).

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The electronic configuration of sulfur is 1s^22s^22p^63s^23p^4.

Because sulfur belongs to Group 16, it has 6 valence electrons.

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