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Marizza181
3 months ago
13

Two long straight wires enter a room through a window. One carries a current of 2.9A into the room, while the other carries a cu

rrent of 4.4 out of the room. Calculate the magnitude (in T.m) of the path integral of B.ds around the window frame.
Physics
1 answer:
ValentinkaMS [3.4K]3 months ago
4 0

Answer and Explanation:

currents i = 2.9 A

           i ' = 4.4 A

The magnitude (in T.m) of the path integral of B.dl around the window frame is calculated as = μo * the enclosed current

          = μo* ( i ' - i )

According to Ampere's law

where μo = permeability of free space = 4π * 10 ^-7 H/m

Substituting the values gives us the magnitude (in T.m) of the path integral of B.dl = (4π*10^-7)(2.9+4.4)

                                 = 1.884 * 10^-6 Tm

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