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Marizza181
15 hours ago
13

Two long straight wires enter a room through a window. One carries a current of 2.9A into the room, while the other carries a cu

rrent of 4.4 out of the room. Calculate the magnitude (in T.m) of the path integral of B.ds around the window frame.
Physics
1 answer:
ValentinkaMS [1.1K]15 hours ago
4 0

Answer and Explanation:

currents i = 2.9 A

           i ' = 4.4 A

The magnitude (in T.m) of the path integral of B.dl around the window frame is calculated as = μo * the enclosed current

          = μo* ( i ' - i )

According to Ampere's law

where μo = permeability of free space = 4π * 10 ^-7 H/m

Substituting the values gives us the magnitude (in T.m) of the path integral of B.dl = (4π*10^-7)(2.9+4.4)

                                 = 1.884 * 10^-6 Tm

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If a radio wave has a period of 1 μs what is the wave's period in seconds
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Answer:

10^{-6} s


The period of a wave is the duration it takes to complete one full oscillation, such as from one peak to the next trough.

Since the period is expressed in microseconds, it needs to be converted into seconds.

The conversion is:

1\mu s=10^{-6} s


Accordingly, the wave's period in seconds is 10^{-6} s
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16 days ago
The Hall effect can be used to calculate the charge-carrier number density in a conductor. If a conductor carrying a current of
kicyunya [1025]

Answer:

6.6*10^{27}e/m^3

Explanation:

When calculating Hall voltage, it is crucial to have the current, magnetic field strength, length, area, and number of charge carriers available. The Hall voltage can be expressed using the equation:

V_h = \frac{iB}{neL}

Where:

i= the current

B= the magnetic field strength

L = the length

n = the number of charge carriers

e= charge of an electron

We need to replace values and solve for n:

n= \frac{iB}{V_h e L}

n= \frac{2*1.2}{4.5*10^{-6}*5^10^{-3}*1.6*10^{-19}}

n= 6.6*10^{27}electron.m^{-3}

As a result, the charge carrier density is 6.6*10^{27}e/m^3

5 0
7 days ago
4. Susan observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered why changes
ValentinkaMS [1149]
The expected measurements should range as follows: 5, 10, 15, 20, and 25 meters.
3 0
5 days ago
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Mrs. Gonzalez is about to give birth and Mr. Gonzalez is rushing her to the hospital at a speed of 30.0 m/s. Witnessing the spee
Ostrovityanka [942]

Answer: The frequency is 1714.3 Hz

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13 days ago
Rosa studies the position-time graph of two race cars. A graph titled Position versus Time shows time in hours on the x axis, nu
Sav [1105]

Answer:

B. Truck X was ahead, not truck Y.

Explanation:

Let's analyze the information provided.

Truck X moved from the point (0,20) to (2.8,50). This indicates that it began at the 20th kilometer and reached 50 km in 2.8 hours. Thus, its speed is v1 = (s2 - s1) / t

v1 = (50 - 20) / 2.8

v1 = 10.7 km/h

Given that it started from the 20th km, it indeed had a head start. Since the line on the graph is linear, this shows its speed was constant without any change in direction.

On the other hand, Truck Y's movement went from the origin (0,0) to (5,20), meaning it took 5 hours to travel 20 km, resulting in a speed of v2 = 20 / 5

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7 days ago
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