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7 days ago

What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect?

Physics

2 answers:

ValentinkaMS [1.1K]7 days ago

6 0

Answer:

1.05 × 10^15 Hz.

Explanation:

The minimal energy of the photon is E = 6.94×10^-19 J.

Planck's constant is noted as h = 6.626 × 10^-34 J s.

Thus, the minimum frequency necessary to emit electrons from titanium through the photoelectric effect is given by E = h. ν.

Where ν represents frequency.

ν = E / h

ν = 6.94×10^-19 J / 6.626 × 10^-34 J s

= 1.05 × 10^15 / s

= 1.05 × 10^15 Hz.

kicyunya [1K]7 days ago

4 0

E = h x f 

Thus: 

f = E / h 
f = 4.41•10^-19 / 6.62•10^-34 
f = 6.66•10^14 Hz (s^-1) 

b/ What is the wavelength of this light? 
------------------------------ 

λ = c / f 
λ = 3•10^8 / 6.66•10^14 
λ = 4.50•10^-7 m

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