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olga nikolaevna
3 months ago
8

A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal compone

nt of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed?

Physics
2 answers:
Softa [3K]3 months ago
4 0

If my calculations are accurate, the angle is 67.5 degrees.

Yuliya22 [3.3K]3 months ago
3 0

Explanation:

Given:

The applied force magnitude is F = 15 N.

The horizontal force component is F_x=4.5\ N.

The angle above the horizontal can be found using the relationship:

F_x=F\ cos\theta

4.5=15\ cos\theta

\theta=cos^{-1}(\dfrac{4.5}{15})

\theta=72.54^{\circ}

Thus, the angle between the force direction and the surface is 72.54 degrees, representing the required answer.

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