Pilobolus is a genus of fungi commonly found on dung and known for launching its spores a large distance for a sporangiophore on
1 answer:
1) The work performed on the spores is
2) The spores land 0.32 m away
Explanation:
1)
According to the work-energy principle, the work done on the spores equals their change in kinetic energy:
where
W is work done
m represents the spore's mass
v is the final velocity
u is the initial velocity
Given:
spore mass =
initial velocity u = 0 (starting from rest)
final velocity v = 7.0 m/s
Calculating the work:
2)
The spores follow projectile motion, moving along a parabolic trajectory made of two motions:
- Constant speed horizontally
- Vertically accelerated due to gravity
Considering vertical motion first, using kinematics:
where
s = 0.01 m (shooting height)
u = 0 (no initial vertical velocity, horizontal ejection)
t = time of flight
g = acceleration due to gravity
Solving for t:
Now for horizontal displacement, when velocity is constant:
where
horizontal velocity =
time t = 0.045 s
Calculating distance d:
Thus, the spores land 0.32 meters away.
Learn more about work:
Learn more about projectile motion:
#LearnwithBrainly
You might be interested in
The question pertains to the change in frequency of a wave noted by an observer moving in relation to the source, indicating that the concept to invoke is "Doppler's effect."
The standard formula for the Doppler effect is:
-- (A)
Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.
Where,
g = Speed of sound = 340m/s.
= Velocity of the observer relative to the medium =?.
= Velocity of the source in relation to the medium = 0 m/s.
= Frequency emitted from the source = 400 Hz.
= Frequency recognized by the observer = 408 Hz.
Substituting the given values into equation (A) will yield:
Solving the above will result in,
= 6.8 m/s
The correct result = 6.8m/s
The standard formula for the Doppler effect is:
Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.
Where,
g = Speed of sound = 340m/s.
Substituting the given values into equation (A) will yield:
Solving the above will result in,
The correct result = 6.8m/s
Answer:
Explanation:
We start with the fact that
Initially, the spacecraft was at rest, u = 0The final velocity of the rocket is given as v = 11 m/sThe distance that the rocket covers during acceleration is given as d = 213 mWe seek to determine the acceleration that the occupants of the spacecraft experience during launch, which is derived from the principles of kinematics. By applying thethird motion equation we can find the acceleration.
Thus, the acceleration felt by those inside the spacecraft is .