Miguel Rodriguez Borrowed $400 from his brother Julio to pay for books and tuition. He agreed to pay Julio in 6 months with simp

Answer:

1.4in

Step-by-step explanation:

Length of Photo = 4in

Width of Photo = 3in

Unknown:

Value of X =?

Solution:

Following these steps:

  Area of a rectangle  = l x w

Considering the photo is rectangular; area of photo:

  Area of photo  = 4in x 3in = 12in²

For the advertisement's area;

   Length of ad  = 4 + x

   Width of ad = 3 + x

Based on the relation that

                  the area of the photo  = area of ad

                           12in²  = area of ad

                   Area of ad  = 24in²

Advertising Area:

             (4 + x) (3 + x)  = 24

               12 + 4x + 3x + x² = 24

                12 + 7x + x²  = 24

                       x² + 7x = 24 - 12

                       x² + 7x = 12

                     x² + 7x - 12  = 0

                    Using the quadratic formula where

     a  = 1, b = 7 and c = -12

          x  =

     

          x =   or

          x  = 1.4  or  -8.4

therefore the answer is 1.4in

x is 1.4in

Answer:

The null hypothesis is stated as H₀: μ = 100

The alternative hypothesis is Hₐ: μ < 100

Evidence suggests that the average location in Wade Tract is 100

Step-by-step explanation:

We define our null hypothesis as H₀: μ = 100, where the average location of trees in the Wade Tract amounts to 100.

Our alternative hypothesis thereby is stated as Hₐ: μ < 100 at a 95% confidence level.

Proposed average location in Wade Tract is μ = 100.

The sample mean computes to = 99.74.

The standard deviation is s = 58.

The sample size n = 584.

Using the t-test formula yields the following results:

Consequently, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We calculate = -1.65

Substituting values into the t-test formula gives t = -0.108338, producing a p-value of p = 0.4569, which exceeds α, hence we accept the null hypothesis, indicating that there is adequate statistical evidence supporting the average location of Wade Tract = 100.

To resolve this question, simply tally the probabilities of the options. The likelihood of a pitch not crossing the plate being a strike is non-existent; thus, P(A | D) = 0. This is true as it calculates to 0/0+20= 0. The likelihood of a pitch not over the plate being a ball is complete; therefore, P(B | D) = 1. This holds true as it equals 20/20+0= 1. The likelihood of a pitch over the plate being a strike is 10:15. It’s incomplete but seems correct; it can be calculated as 10/10+5= 10/15 = 2/3. The probability for a pitch over the plate labeled a ball is 5:10; therefore, P(B | C) = 0.5.