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NemiM
20 days ago
12

Consider 500 g of silver (atomic mass 107 g/mol). Assume that the temperature is high enough that equipartition applies. We heat

the silver by immersing it in water; by measuring the temperature change of the water we compute that 300 J of heat energy entered the silver.
What was the change in temperature of the silver?

A. 2.57 K
B. 0.6 K
C. 4.99 K
D. 169 K
E. 0.0466 K
Physics
1 answer:
ValentinkaMS [2.4K]20 days ago
3 0

Answer:

A. 2.57 K

Explanation:

Using the specific heat capacity,

Q = cmΔT........................ Equation 1

Where Q = Heat energy absorbed by silver, m = mass of silver, c = specific heat capacity for silver, ΔT = temperature change of the silver.

Rearranging gives ΔT as the subject of the equation

ΔT = Q/cm................... Equation 2

Provided: Q = 300 J, m = 500 g = 0.5 kg

Constant: c = 233 J/kg.K

Inserting values into equation 2 yields

ΔT = 300/(0.5×233)

ΔT  = 300/116.5

ΔT = 2.57 K

Therefore, the correct answer is A. 2.57 K

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Answer:

ΔL = MmRgt / (2m + M)

Explanation:

The system starts from rest, so the change in angular momentum correlates directly to its final angular momentum.

ΔL = L − L₀

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To determine the angular velocity ω, begin by drawing a free body diagram for both the pulley and the block.

For the block, two forces act: the weight force mg downward and tension force T upward.

For the pulley, three forces are present: weight force Mg down, a reaction force up, and tension force T downward.

For the sum of forces in the -y direction on the block:

∑F = ma

mg − T = ma

T = mg − ma

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∑τ = Iα

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T = ½ Ma

Substituting gives:

mg − ma = ½ Ma

2mg − 2ma = Ma

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αR = 2mg / (2m + M)

α = 2mg / (R (2m + M))

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ω = αt + ω₀

ω = 2mg / (R (2m + M)) t + 0

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ΔL = ½ MR² × 2mgt / (R (2m + M))

ΔL = MmRgt / (2m + M)

3 0
1 month ago
How long does it take to raise the temperature of the air in a good-sized living room (3.00m×5.00m×8.00m) by 10.0∘C? Note that t
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