Answer:
0.018 J
Explanation:
The work required to bring the charge from infinity to the point P is equal to the change in its electric potential energy. This can be expressed as
where
represents the charge's magnitude
and signifies the potential difference between point P and infinity.
After substituting into the formula, we arrive at
Response:
For a transition metal complex in solution exhibiting an absorption peak at 450 nm, which falls within the blue section of the visible spectrum, the corresponding (complementary) color of this solution is orange (option B).
Rationale:
The amount of UV-visible light absorbed indicates that some electromagnetic radiation successfully passes through the sample and is perceivable by the human eye. Thus, the color apparent in the visible spectrum of a complex aligns with the wavelengths of light it allows to pass rather than those it absorbs. The color that is absorbed will be complementary to the one that is transmitted.
In the accompanying image, you can view the associated wavelengths alongside their respective colors. By identifying the wavelength associated with the absorbed color, you will be able to see the complementary color that is visible or reflected.
For a transition metal complex in solution exhibiting an absorption peak at 450 nm, which falls within the blue section of the visible spectrum, the corresponding (complementary) color of this solution is orange (option B).
Answer:
A) 328 m
B) 80.22 m/s
C) 8.18 sec
Explanation:
A)
The rocket's initial acceleration is 2.25 m/s²
Time until engine failure is 15.4 s
Initial velocity u during takeoff = 0 m/s
Distance covered while the engine is functional =?
We apply Newton's laws for this calculation
S = ut + a
Here, S represents the distance traveled under the rocket's thrust
S = (0 x 15.4) + (2.25 x
)
S = 0 + 266.81 m = 266.81 m
Before the engine fails, the final velocity can be found using:
v = u + at
v = 0 + (2.25 x 15.4) = 34.65 m/s
Once the engine fails, the rocket decelerates under gravitational pull at g = -9.81 m/s² (acting downwards)
The upward initial velocity when freefall begins is v = 34.65 m/s
The final velocity is reached at peak height, where the rocket halts, therefore:
u = 0 m/s
The distance covered during this freefall will be s =?
Utilizing the equation
=
+ 2gs
=
+ 2(-9.81 x s)
0 = 1200.6 - 19.62s
-1200.6 = -19.62s
s = -1200.6/-19.62 = 61.19 m
Thus,
Maximum Height = 266.81 m + 61.19 m = 328 m
B)
At maximum height, the rocket’s initial upward velocity drops to 0 m/s (the rocket completely stops)
The descent occurs freely under g = 9.81 m/s² (acting downwards)
The distance covered during the fall will be 328 m
Final velocity v just prior to impact =?
Applying =
+ 2gs
=
+ 2(9.81 x 328)
= 0 + 6435.36
v = = 80.22 m/s
The time taken before reaching the pad is found as follows
v = u + gt
80.22 = 0 + 9.81t
t = 80.22/9.81 = 8.18 sec