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Alik
2 months ago
6

A segment of wire of total length 2.0 m is formed into a circular loop having 5.0 turns. If the wire carries a 1.2-A current, de

termine the magnitude of the magnetic field at the center of the loop.
Physics
1 answer:
Keith_Richards [3.2K]2 months ago
8 0

Answer:

The magnetic field at the loop's center is B=5.89\times 10^{-5}\ T.

Explanation:

The total wire length provided is 2 m with 5 circular loops formed.

Hence,

5\times ( 2\pi r)=2 \ m.\\\\r=\dfrac{1}{5 \pi}=0.064\ m.

The magnetic field at the center of a loop can be calculated as:

B=N\dfrac{\mu_o i}{2r}

Substituting the values into the above equation results in:

B=5\times \dfrac{4\pi\times 10^{-7}\times 1.2}{2\times 0.064}\\\\B=5.89\times 10^{-5}\ T.

Thus, we arrive at the required answer.

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