A segment of wire of total length 2.0 m is formed into a circular loop having 5.0 turns. If the wire carries a 1.2-A current, de

Question

3 months ago

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termine the magnitude of the magnetic field at the center of the loop.

1 answer:

Keith_Richards [3.2K] · Answer 1 · 2026-03-11T19:40:54+03:00

Answer:

The magnetic field at the loop's center is $B=5.89\times 10^{-5}\ T.$

Explanation:

The total wire length provided is 2 m with 5 circular loops formed.

Hence,

$5\times ( 2\pi r)=2 \ m.\\\\r=\dfrac{1}{5 \pi}=0.064\ m.$

The magnetic field at the center of a loop can be calculated as:

$B=N\dfrac{\mu_o i}{2r}$

Substituting the values into the above equation results in:

$B=5\times \dfrac{4\pi\times 10^{-7}\times 1.2}{2\times 0.064}\\\\B=5.89\times 10^{-5}\ T.$

Thus, we arrive at the required answer.