Answer:
fcosθ + Fbcosθ =Wtanθ
Explanation:
Refer to the provided diagram in the attachment
fx= fcosθ (fx: x-direction component of friction force; f: frictional force)
Fbx= Fbcosθ (Fbx: x-direction component of braking force; Fb: braking force)
Wx= Wtanθ (Wx: x-direction component of weight; W: weight of the semi)
Sum of forces in the x-direction = 0
fx + Fbx = Wx
fcosθ + Fbcosθ =Wtanθ
Answer:
v = 54.2 m/s
Explanation:
We can utilize conservation of energy to solve this issue.
Initial condition Higher
Em₀ = U = m g h
Final condition. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ (2gh)
Now let's perform the calculation
v = √ (2 * 9.8 * 150)
v = 54.2 m/s
You would gain an additional 40/60 of energy, which equals 2/3. To find the actual energy consumption, multiply 5/3 by the needed energy.
Answer:
11.56066 m/s
Explanation:
m = Mass of individual
v = Velocity of individual = 13.4 m/s
g = Gravitational acceleration = 9.81 m/s²
v' = Velocity of the individual after dropping
At the surface, kinetic and potential energy will equalize

The cliff's height is 9.15188 m
Define fall height as h' = 2.34 m

The person's speed is 11.56066 m/s
The city evaluates the continuous increase of carbon monoxide from different origins each year. According to calculations, in the year "C: 2019"<span> (rounded to the closest whole number), the concentration of CO will surpass the allowed threshold.
If this is not correct, feel free to inform me and I will find out the right answer. However, I am confident this is accurate.:) </span>