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makvit
2 days ago
12

An object weighs 7.84 N when it is in air and 6.86 N when it is immersed in water of density 1000 kg/m3. What is the density of

the object?
Physics
1 answer:
Sav [3K]2 days ago
3 0
The object's density is 8000 kg/m^3. The object's weight in air is 7.84 N while it measures 6.86 N when submerged in water, where the density of water is 1000 kg/m^3. According to Archimedes' principle, an immersed object experiences an upward buoyant force equivalent to its loss of weight in the fluid. By calculating the weight difference (7.84 - 6.86 = 0.98 N) and employing the standard equations relating density and volume, we find that 10^-4 m^3 corresponds to a density of 8000 kg/m^3.
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How many turns should a 10-cm long solenoid have if it is to generate a 1.5 x 10-3 t magnetic field on 1.0 a of current?
kicyunya [3140]

This problem can be solved using Ampere’s Law:

<span>Bh = μoNI </span>

In this equation:

B = Magnetic Field

h = length of the coil

<span>μo = permeability = 4π*10^-7 T·m/A</span>

N = number of coil turns

I = current

Given values are B = 0.0015T, I = 1.0A, h = 10 cm = 0.1m<span>

Utilizing Ampere's law to determine the number of turns:
This can be rearranged to:
<span>N = Bh/μoI</span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4

</span>

<span>Final answer: 119.4 turns</span>

3 0
19 days ago
True or False: Molecules in a gas resist crowding and get as far apart as possible. Free electrons also resist crowding and get
ValentinkaMS [3319]

Answer:

This assertion is inaccurate.

Explanation:

The random nature of gas molecules results in their erratic motion and occasional collisions. While it is true that they tend to avoid being tightly packed, achieving the maximum separation from each other is not always feasible due to their lack of fixed positions. Consequently, gas molecules in a container cannot consistently maintain the furthest distance from their neighboring molecules.

In contrast, the separation among electrons is primarily influenced by repulsive forces, not random movement as in gases. Electrons maintain distance as a result of repulsion between similarly charged particles. Therefore, the arrangement of electrons on a charged copper sphere occurs not from a random distribution but rather due to repulsion, establishing a set distance between them.

4 0
29 days ago
If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.
ValentinkaMS [3319]
V = I * R, where V signifies voltage, I represents current, and R is resistance. According to Ohm's law, to determine the current through the wire, resistance is required. In theory, if the wire had zero resistance, it would lead to infinite current, which is not feasible. This negligible resistance could refer to the internal resistance of the battery rather than the wire itself. 
7 0
3 days ago
A plane monochromatic radio wave (λ = 0.3 m) travels in vacuum along the positive x-axis, with a time-averaged intensity I = 45
serg [3462]
The magnetic field is calculated to be -6.137 × T. Explanation: Given the radio wave wavelength of λ = 0.3 m and an intensity of I = 45 W/m² at times t = 0 and t = 1.5 ns, we determine Bz at the origin. We use the intensity formula relating to the electric field, which incorporates the known intensity of 45, the speed of light c = 3 × m/s², and ∈o as 8.85 × C²/N.m², leading us to E = 184.15. Consequently, applying the equations, we find B = -6.137 × T at the z-axis.
8 0
18 days ago
If the wire is replaced by an infinite current sheet with density Js = 0.40 A/m, what would be the magnetic flux (in T · m2) thr
Sav [3027]

Answer:

Clarification:\phi _{B} =0.855 T-m^{-2}

Considering the following data the density of the current sheet is 0.40 A/m

The length a = 0.27 m

and the width b = 0.63 m

For an infinite sheet, the magnetic field is described as

The magnetic flux is given as

B = \mu _{O}J

magnetic flux =

\phi _{B} = BA

                   = \mu _{O}Jab

                   = 4\pi *0.40*0.27*0.63

\phi _{B} =0.855 T-m^{-2}

6 0
12 days ago
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