A 600 kg car is at rest, and then accelerates to 5 m/s.

Answer:

Explanation:

The friction created between the tire and the ground generates thermal energy as force is applied during skidding.

The mentioned force relates to half the impact on the rear tire, resulting in a calculated normal force of,

The work executed is determined by the frictional force and the distance covered,

Where

The thermal energy produced from the work done is,

B) 14.0 N

To address this inquiry, we need to evaluate the kinetic energy of the box before and after crossing the rough section. The kinetic energy is given by the formula:

E = 0.5 M V^2

where

E = Energy

M = Mass

V = velocity

Now, utilizing the known data, we compute the energy prior and post.

Before:

E = 0.5 M V^2

E = 0.5 * 13.5kg * (2.25 m/s)^2

E = 6.75 kg * 5.0625 m^2/s^2

E = 34.17188 kg*m^2/s^2 = 34.17188 joules

After:

E = 0.5 M V^2

E = 0.5 * 13.5kg * (1.2 m/s)^2

E = 6.75 kg * 1.44 m^2/s^2

E = 9.72 kg*m^2/s^2 = 9.72 Joules

Hence, the box consumed energy equal to 34.17188 J - 9.72 J = 24.451875 J over a length of 1.75 meters. Next, we will calculate the loss per meter by dividing the energy loss by the distance traversed.
24.451875 J / 1.75 m = 13.9725 J/m = 13.9725 N

When we round to one decimal point, we arrive at 14.0 N, which corresponds with option “B.”

Answer:

a)

b) the distance the motorcycle covers is 155 m

Explanation:

Let denote the variables. Next, we analyze the motion equation for the accelerating motorcycle alongside the constant speed of the car:

where:

represents the motorcycle's speed at time 2

is the steady velocity of the car

indicates the initial speeds of both vehicle types at time 1

d signifies the distance separating the car and motorcycle at the initial moment

x is the distance the car travels from time 1 to time 2

Solving the equations provides:

For the second query, we determine x+d by applying the car’s motion equation to compute x:

The only scenarios where one can derive dependable data from a noncontact measurement of an insulator's charge state are with free insulative sheets or those that have a grounded conductor backing. In each of these instances, the electric field generated by the charge plays a crucial role.