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yan
10 days ago
7

A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo

w, sending the light through a diffraction grating, and measuring the positions of first-order spectral lines on a detector 15.0 cm behind the grating. Unfortunately, she has lost the card that gives the specifications of the grating. Fortunately, she has a known compound that she can use to calibrate the grating. She heats the known compound, which emits light at a wavelength of 501 nm, and observes a spectral line 9.95 cm from the center of the diffraction pattern. PART A:
What is the wavelength emitted by compound A that have spectral line detected at position 8.55 cm?


PART B:


What is the wavelength emitted by compound B that have spectral line detected at position and 12.15 cm?
Physics
1 answer:
Yuliya22 [2.4K]10 days ago
4 0
a) λ = 189.43 × 10⁻⁹ m b) λ = 269.19 × 10⁻⁹ m

Explanation: The expression that describes the diffraction network is

d sin θ= m λ

where m denotes the diffraction order.

Using trigonometry, we can determine the angle as follows:

tan θ = y / L

Since the diffraction spectrum is measured at minimal angles, tan θ simplifies to sin θ.

We replace with

d y / L = m λ

Using the first order where m = 1:

Now we need to find the line separation (d)

d = λ L / y

d = 501 × 10⁻⁹ × 9.95 × 10⁻² / 15 × 10⁻²

d = 332.33 × 10⁻⁹ m

Next, we find the wavelength of the other compound:

λ = d y / L

λ = 332.33 × 10⁻⁹ × 8.55 × 10⁻²/15 × 10⁻²

λ = 189.43 × 10⁻⁹ m

For Part B, the compound's wavelength is

λ = 332.33 × 10⁻⁹ × 12.15 × 10⁻² / 15 × 10⁻²

λ = 269.19 × 10⁻⁹ m.
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ValentinkaMS [2425]

Answer:

The rotational angular speed is measured at 1.34 rad/s.

Explanation:

Considering the following parameters,

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T\sin\theta=m\omega^2 r

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\omega=\sqrt{\dfrac{g\tan\theta}{(d+L\sin\theta)}}

Substituting the value into the equation

\omega=\sqrt{\dfrac{9.8\tan45.0}{5.90+3.40\sin45.0}}

\omega=1.34\ rad/s

Thus, the angular speed of rotation computes to 1.34 rad/s.

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Point charge A with a charge of +4.00 μC is located at the origin. Point charge B with a charge of +7.00 μC is located on the x
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Response:

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A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w
Keith_Richards [2256]
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3 days ago
Alicia intends to swim to a point straight across a 100 m wide river with a current that flows at 1.2 m/s. She can swim 2.5 m/s
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Answer:

θ = 61.3°

Alicia must swim at an angle of 61.3°

Explanation:

Parameters given include:

Width of the river = 100 m

Alicia's speed in still water = 2.5 m/s

Speed of river's current = 1.2 m/s

The angle she needs to swim can be determined by combining the velocities, taking into account the current's influence.

Her swimming speed aimed against the current must offset the current's velocity;

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4 0
18 days ago
A block moves at 5 m/s in the positive x direction and hits an identical block, initially at rest. A small amount of gunpowder h
Yuliya22 [2420]

Answer:

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Explanation:

Based on the law of conservation of momentum,

mv_o=m(v_1 + v_2)where m represents mass, v_o is the initial speed before impact, v_1 and v_2 are the velocities of the impacted object after the collision and of the originally stationary object after the impact.

5m=m(v_1 +v_2)

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2v_o^{2}=v_1^{2} + v_2^{2}

Substituting the initial velocity of 5 m/s provides the equation needed to proceed.v_o

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50=(5-v_2)^{2}+ v_2^{2}

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By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.

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