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yan
1 month ago
7

A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo

w, sending the light through a diffraction grating, and measuring the positions of first-order spectral lines on a detector 15.0 cm behind the grating. Unfortunately, she has lost the card that gives the specifications of the grating. Fortunately, she has a known compound that she can use to calibrate the grating. She heats the known compound, which emits light at a wavelength of 501 nm, and observes a spectral line 9.95 cm from the center of the diffraction pattern. PART A:
What is the wavelength emitted by compound A that have spectral line detected at position 8.55 cm?


PART B:


What is the wavelength emitted by compound B that have spectral line detected at position and 12.15 cm?
Physics
1 answer:
Yuliya22 [3.3K]1 month ago
4 0
a) λ = 189.43 × 10⁻⁹ m b) λ = 269.19 × 10⁻⁹ m

Explanation: The expression that describes the diffraction network is

d sin θ= m λ

where m denotes the diffraction order.

Using trigonometry, we can determine the angle as follows:

tan θ = y / L

Since the diffraction spectrum is measured at minimal angles, tan θ simplifies to sin θ.

We replace with

d y / L = m λ

Using the first order where m = 1:

Now we need to find the line separation (d)

d = λ L / y

d = 501 × 10⁻⁹ × 9.95 × 10⁻² / 15 × 10⁻²

d = 332.33 × 10⁻⁹ m

Next, we find the wavelength of the other compound:

λ = d y / L

λ = 332.33 × 10⁻⁹ × 8.55 × 10⁻²/15 × 10⁻²

λ = 189.43 × 10⁻⁹ m

For Part B, the compound's wavelength is

λ = 332.33 × 10⁻⁹ × 12.15 × 10⁻² / 15 × 10⁻²

λ = 269.19 × 10⁻⁹ m.
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1 month ago
An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista
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Answer:

        h = 12.8 cm

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