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Dimas
2 months ago
11

2.00 g of an unknown volatile liquid was placed in a flask with a total volume of 265.0 mL. The cover of the flask has only a pi

nhole, which allows the internal pressure to equilibrate with the outside pressure. The temperature was raised to 100.00C by placing the flask in a constant temperature water bath. At this temperature, it was found that only 0.581 g of the liquid substance remained in the flask. A barometer in the lab showed the pressure to be 752 mm Hg. What's the molar mass of the unknown liquid?
Chemistry
1 answer:
eduard [2.7K]2 months ago
4 0

Answer:

165.52 g/mol

Explanation:

As the temperature raised to 100 C, part of the initial mass of liquid converted to gas, specifically 2.00-0.581 = 1.419 g.  This gas occupies a volume of around 265 mL, at a pressure of 752 mm Hg and a temperature of 100 C. Assuming this gas behaves ideally, we can estimate its molecular weight M_Wusing the ideal gas law:

PVM_{W}=RTm with R= 0.082 atm L/(mol K)

or M_{W}=\frac{RTm}{PV}

Before applying the formula, we convert volume to L (1L=1000 mL), pressure to atm (1 atm=760 mmHg), and temperature to K (K=273+C).

265/1000 = 0.265 L

752/760=0.989 atm

273+100=373 K

Ultimately, inserting values into the formula gives

\frac{0.082*1.419*373}{0.989*0.265}=165.52 g/mol

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Tems11 [2777]

Response:

Ethanol serves as a reducing agent.(C_2H_5OH)

The lowest integer coefficient for MnO_4^- in the balanced equation is 4

Clarification:

A redox reaction, or oxidation-reduction reaction, is defined as one in which oxidation and reduction processes occur simultaneously.

Oxidation is the process whereby a substance loses electrons, resulting in an increase in oxidation state. In contrast, reduction entails a substance gaining electrons, leading to a decrease in oxidation state.

Reducing agents enable other substances to undergo reduction while becoming oxidized themselves.

Conversely, oxidizing agents facilitate other substances' oxidation while being reduced in the process.

For the chemical reaction in question, the half-reaction would be:

Oxidation:

Reduction:

To balance the oxygen atoms on both sides

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

For oxidation:

For reduction:

C_2H_6O\rightarrow C_2H_4O_2

MnO_4^-\rightarrow Mn^{2+}Then balance the hydrogen atoms on both sides.

  • For oxidation:
For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2

Lastly, balance the charge.MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • For oxidation: For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

To balance the electrons, multiply the oxidation reaction by 5 and the reduction by 4 before combining both equations for a balanced redox reaction.

MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2OOxidation:

  • Reduction:
The finalized balanced chemical equation in acidic conditions will be:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In this redox process, ethanol acts as the reducing agent while the permanganate ion serves as the oxidizing agent.

4 0
2 months ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
VMariaS [2998]

Answer:

The heat capacity of the calorimeter is C_c = 54.4 \frac{J}{c}

Explanation:

Given the data

Heat supplied Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Change in temperature = ΔT = 35.82 - 24.58 = 11.24 °C

From the conditions provided

Q = m_w C_w ΔT + C_c ΔT

Plugging all values into the above equation yields

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This represents the heat capacity of the calorimeter.

7 0
3 months ago
Select all the element(s) from the periodic table shown that will form an ionic compound with a metal M and a nonmetal X and a f
VMariaS [2998]

Response:

Sulfate- SO4^2-

Sulfite- SO3^2-

Permanganate- MnO4

Carbonate- CO3^2

Clarification:

KEEP GOING WITH YOUR STUDIES!

4 0
3 months ago
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