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Dimas
8 days ago
11

2.00 g of an unknown volatile liquid was placed in a flask with a total volume of 265.0 mL. The cover of the flask has only a pi

nhole, which allows the internal pressure to equilibrate with the outside pressure. The temperature was raised to 100.00C by placing the flask in a constant temperature water bath. At this temperature, it was found that only 0.581 g of the liquid substance remained in the flask. A barometer in the lab showed the pressure to be 752 mm Hg. What's the molar mass of the unknown liquid?
Chemistry
1 answer:
eduard [2.7K]8 days ago
4 0

Answer:

165.52 g/mol

Explanation:

As the temperature raised to 100 C, part of the initial mass of liquid converted to gas, specifically 2.00-0.581 = 1.419 g.  This gas occupies a volume of around 265 mL, at a pressure of 752 mm Hg and a temperature of 100 C. Assuming this gas behaves ideally, we can estimate its molecular weight M_Wusing the ideal gas law:

PVM_{W}=RTm with R= 0.082 atm L/(mol K)

or M_{W}=\frac{RTm}{PV}

Before applying the formula, we convert volume to L (1L=1000 mL), pressure to atm (1 atm=760 mmHg), and temperature to K (K=273+C).

265/1000 = 0.265 L

752/760=0.989 atm

273+100=373 K

Ultimately, inserting values into the formula gives

\frac{0.082*1.419*373}{0.989*0.265}=165.52 g/mol

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