The box plots compare the exam scores of Ms. Dobson’s class to the rest of the students who took the test in the district.

Answer: On average, a pet's weight during this vet visit is approximately 2.4 pounds away from 12.9 pounds.

If the MAD for another day's weights was 1.5, then that day’s weights would be less variable compared to the weights of pets seen today.

Step-by-step explanation:

Given: The data in the table outlines the weights of animals visiting a vet one day, in pounds.

Mean = 12.9

Median= 12.0

Mode = 12.0

Mean Absolute Deviation = 2.4

It’s understood that the mean absolute deviation (MAD) of a dataset indicates the average distance between each data point and the mean. It reflects the variation present in the dataset.

Therefore, the average weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.

Moreover, if another day had a MAD of 1.5, and since 1.5 < 2.4,[TAG_42]]

it implies that the weights on that day would be less variable compared to those of pets encountered on this day.

Answer:

First, it's essential to define the equation that characterizes the function.

The investment is $200 with an interest rate of 5%, where y represents the money after x periods.

After one period, the amount of money grows to 200 plus 5% interest, resulting in 200 + 5%(200) = 200 (1 +5%) = 200 (1 + 0.05) = 200 (1.05)

After two periods, the total is 200(1.05)*(1.05) = 200 (1.05)^2

After three periods, it will be 200 (1.05)^3

Consequently, it can be inferred that after x periods, y = 200 (1.05)^x

Next, this function can be analyzed to project the graph's shape and significant points.

The answers derive from the initial value and the growth factor.

The initial value occurs when x = 0, giving y = 200 (1.05)^0 = 200*1 = 200

The growth factor is 1.05, indicating each subsequent value is multiplied by 1.05.

Step-by-step explanation:

Answer:

1) (2.2, -1.4)

2) (1.33, 1)

Detailed solution:

Question 1)

We are provided with two linear equations representing lines, and we need to find the intersection point that solves the system.

The lines given are:

Line 1 equation:

This line passes through points (0, 2.5) and (2.2, -1.4).

Line 2 equation:

The second line goes through (0, -3) and (2.2, -1.4).

According to the graph and data, the solution to the system is the coordinate where both lines intersect.

The solution to a system of linear equations is the coordinate pair common to both lines, i.e., the intersection point.

Here, both lines share the point (2.2, -1.4), indicating it is their intersection and the solution.

Therefore, the solution for question 1 is (2.2, -1.4).

Question 2)

The equations given are:

y = 1.5x - 1               Equation 1

y = 1                           Equation 2

The method of substitution can be used to find the solution.

Replacing y from Equation 2 into Equation 1 gives:

1 = 1.5x - 1

Add 1 to both sides:

2 = 1.5x

Dividing both sides by 1.5 yields:

x = 2/1.5

x = 1.33

y = 1

Thus, the solution of the system is (1.33, 1).

To understand the stacking of cups, start with the height of one cup plus its lip's height. Following that, continue to add the height of each lip until the desired total height is reached. Thus, the total number of cups needed is 19.