Result: -50.005 kJ
Details:
Provided Data
mass of the system = 10 kg
work done = 0.147 kJ/kg
Elevation change 
initial speed 
Final Speed 
Specific internal Energy 
according to the first Law of thermodynamics


where KE represents kinetic energy
PE indicates potential energy
U denotes internal Energy



Q = 1.47 + 3.375 - 4.850 - 50
Q = -50.005 kJ
Hypothesis: The liquid will project far.
Independent Variable: Height of the hole.
Dependent Variable: Distance of the squirt.
Constant: All other factors aside from the independent variable, such as the liquid volume.
Control: None that I recognize.
Number of groups: 4
Trials per group: 4
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Answer:
Maximum emf = 5.32 V
Explanation:
Provided data includes:
Number of turns, N = 10
Radius of loop, r = 3 cm = 0.03 m
It made 60 revolutions each second
Magnetic field, B = 0.5 T
We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:

For the maximum emf, 
Therefore,

Hence, the maximum emf generated in the loop is 5.32 V.
Answer:
The pen requires 7.2 mJ of energy to extend.
Explanation:
Provided:
Length = 1.8 cm
Spring constant = 300 N/m
Initial compression = 1.0 mm
Additional compression = 6.0 mm
Total compression = 1.0 + 6.0 = 7.0 mm
We need to determine the energy needed
This energy is equivalent to the variation in spring potential energy


Substitute the values into the formula



Therefore, a total of 7.2 mJ is needed to extend the pen.