50 POINTS! A Boy throws a ball horizontally a distance of 22m downrange from the top of a tower that is 20.0m tall. What is his

Question

2 months ago

7

throwing velocity?

1 answer:

Softa [3K] · Answer 1 · 2026-04-01T07:49:14+03:00

At time $t$ , the ball's horizontal and vertical velocities can be represented as

$v_x=v_{xi}$

$v_y=v_{yi}-gt$

However, since the ball is thrown horizontally, we have $v_{yi}=0$ . The horizontal and vertical positions at time $t$ are

$x=v_{xi}t$

$y=20.0\,\mathrm m-\dfrac g2t^2$

The ball travels a distance of 22 m horizontally from the throw point, thus

$22\,\mathrm m=v_{xi}t$

With this, we determine that the time for the ball to reach the ground is

$t=\dfrac{22\,\rm m}{v_{xi}}$

When it touches down, $y=0$ and

$0=20.0\,\mathrm m-\dfrac{9.8\frac{\rm m}{\mathrm s^2}}2\left(\dfrac{22\,\rm m}{v_{xi}}\right)^2$

$\implies v_i=v_{xi}=11\dfrac{\rm m}{\rm s}$