Although you didn't provide the question, I'm here to clarify the issue and guide you in locating the necessary information.
1) The shark rises at an angle of 13°, calculated as follows:
Vertical ascending speed = 0.85m/s * sin(13°)
Horizontal speed = 0.85m/s * cos(13°)
2) The distance the shark covers while ascending is determined as follows
Vertical ascent length = 50 m
Horizontal distance, y:

This gives y = 50 * tan(13°)
=> y = 11.54 m.
3) In conclusion:
1) The shark traveled 50 m upward vertically and 11.54 m horizontally.
2) To find the length of the path taken by the shark, we can use Pythagoras' theorem:
hypotenuse^2 = (50m)^2 + (11.54m)^2 = 2633.25m^2
hypotenuse = 51.35m
Consequently, the shark swam 51.35 m to surface.