Lavania is studying the growth of a population of fruit flies in her laboratory. After 6 days she had nine more than five times

Answer:

The solution to this problem indicates that Hernry invested $18,000 in stocks and $6,000 in bonds.

Step-by-step explanation:

First, you need to multiply 6 by 3. The outcome is 18, meaning it is three times higher than the bond amount. Next, subtract $24,000 from $18,000, which gives you $6,000, representing the bond investment. Hence, it is three times less than the stocks as the question describes.

The formula representing this scenario is

The answer to this formula is

Initially, you need to formulate the equation.

Next, simplify the expressions.

Afterwards, subtract 5.7 from both sides.

Lastly, divide both sides by 5

The formula for determining the number of ways to select two pairs of sneakers from three pairs labeled A, B, and C is represented by 3C2 (3 combinations of 2), which calculates as 3! / (2!(3 - 2)!) = 3! / (2! x 1!) = (3 x 2) / (2 x 1) = 3. Therefore, the sample space is S = {AB, AC, BC}.

Answer:

We have the following details:

Confidence level = 99%. Hence, the critical value at a 0.01 significance level is provided below:

The margin of error is mentioned in the question as:

Since we lack information about the previous proportion, we need to assume .

Therefore, the required sample size is:

 

 

 

Thus, it requires 664 sample observations.    

The question is missing some information. It should be phrased as follows:

<span><span>A container has 50 electronic components, with 10 identified as defective. If 6 components are randomly selected from the container, what is the probability that at least 4 of them are not defective? Additionally, if 8 components are drawn at random from the container, what is the probability that exactly 3 are defective?

</span>Answers
<span>Part 1.  0.02
Part 2. </span></span>0.0375<span><span>

</span>Explanation
Probability denotes the likelihood of an event occurring. It is computed as:
probability = (Number of favorable outcomes)/(Number of total outcomes)

Part 1
When 6 components are chosen, if 4 are confirmed functioning, then 2 must be defective.
P(at least 4 functional) = 4/40</span>× 2/10
                                            = 1/10 × 1/5
                                            = 1/50
                                            = 0.02

Part 2
Choosing 8 components, if 3 are defective, then 5 are functioning.
P(3 defective) = 3/40 × 5/10
                             = 15/400
                             = 3/80
                            = 0.0375