Answer:
17.35 × 10^(-6) m
Explanation:
Mass; m = 50 kg
Weight; W = 554 N
From the formula:
W = mg
This simplifies to; 554 = 50g
g = 554/50
g = 11.08 m/s²
Also, using the formula;
mg = GMm/r²
hence; g = GM/r²
Rearranging gives;
r = √(GM/g)
With G as a known constant of 6.67 × 10^(-11) Nm²/kg²
r = √(6.67 × 10^(-11) × 50/11.08)
r = 17.35 × 10^(-6) m
Answer
Ceres, Pluto, and Eris are categorized as DWARF PLANETS.
A) Remaining planetesimals formed within the frost line are referred to as ASTEROIDS.
B) METEORITES are fragments of asteroids that have landed on Earth.
C) COMETS are celestial objects that are often visible with their long tails.
D) COMETS are also planetesimals that were left over and originated in the region of the solar system dominated by the jovian planets.
E) Meteor showers are linked to debris from COMETS.
Answer:
= 1,386 m / s
Explanation:
The mechanism behind rocket propulsion is defined by the formula
- v₀ =
ln (M₀ / Mf)
Here, v refers to the initial, final, and relative velocities, while M indicates the masses
The provided values include the relative velocity (see = 2000 m / s) and the initial mass, where the mass of the rocket when loaded is represented as (M₀ = 5Mf)
For our analysis, we assume the rocket begins at rest (v₀ = 0)
Once half of the fuel has burnt, the mass ratio indicates that the current mass is
M = 2.5 Mf
- 0 = 2000 ln (5Mf / 2.5 Mf) = 2000 ln 2
= 1,386 m / s
Answer:
The water level increases more when the cube is above the raft before it sinks.
Explanation:
The principle involved is based on Archimedes' theory, which states that immersing an object in water will raise the initial water level. This means that the height of the water in the container increases. The increase in water volume corresponds to the volume of the submerged object.
We can consider two scenarios: when the steel cube rests on the raft and when it settles at the pool's bottom.
When the cube rests at the pool’s bottom, the volume will indeed rise, and we can ascertain this using the cube's volume.
Vc = 0.45*0.45*0.45 = 0.0911 [m^3]
When an object floats, it's because the densities of the object and water are in equilibrium.
![Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3]](https://tex.z-dn.net/?f=Ro_%7BH2O%7D%3DR_%7Bc%2Br%7D%5C%5Cwhere%3A%5C%5CRo_%7BH2O%7D%3D%20water%20density%20%3D%201000%20%5Bkg%2Fm%5E3%5D%5C%5CRo_%7Bc%2Br%7D%3D%20combined%20density%20cube%20%2B%20raft%20%5Bkg%2Fm%5E3%5D)
The formula for density is:
Ro = m/V
where:
m= mass [kg]
V = volume [m^3]
The buoyant force can be calculated with this equation:
![F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3]](https://tex.z-dn.net/?f=F_%7BB%7D%3DW%3DRo_%7BH20%7D%2Ag%2AVs%5C%5CW%20%3D%20%28200%2B730%29%2A9.81%5C%5CW%3D9123.3%5BN%5D%5C%5C%5C%5C9123%3D1000%2A9.81%2AVs%5C%5CVs%20%3D%200.93%20%5Bm%5E3%5D)
Vs > Vc indicates that the combined volume of the raft and the cube exceeds that of the cube alone resting at the bottom of the pool. Hence, when the cube is positioned above the raft, the water level rises more before it becomes submerged.