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lana66690
1 day ago
5

A rocket in deep space has an exhaust-gas speed of 2000 m/s. When the rocket is fully loaded, the mass of the fuel is five times

the mass of the empty rocket. Part A What is the rocket's speed when half the fuel has been burned?
Physics
1 answer:
Sav [2.2K]1 day ago
3 0

Answer:

 v_{f} = 1,386 m / s

Explanation:

The mechanism behind rocket propulsion is defined by the formula

       v_{f} - v₀ =  v_{r} ln (M₀ / Mf)

Here, v refers to the initial, final, and relative velocities, while M indicates the masses

The provided values include the relative velocity (see = 2000 m / s) and the initial mass, where the mass of the rocket when loaded is represented as (M₀ = 5Mf)

For our analysis, we assume the rocket begins at rest (v₀ = 0)

Once half of the fuel has burnt, the mass ratio indicates that the current mass is    

       M = 2.5 Mf

       v_{f} - 0 = 2000 ln (5Mf / 2.5 Mf) = 2000 ln 2

       v_{f} = 1,386 m / s

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Keith_Richards [2268]

Answer:

1)  g = 4π² / m, 3) on the x-axis we have the pendulum lengths, while the y-axis shows the squared periods.

Explanation:

a) learners can model this system as a simple pendulum, where the angular velocity is given by

         w = √ g / l

Here, angular velocity, frequency, and period are interconnected:

         w = 2π f = 2π / T

Substituting yields:

         T = 2π√ l / g

Using this formula, students can calculate the gravitational acceleration by measuring the period for several pendulum lengths and plotting:

        T² = 4π²  l / g

We plot T² against l.

This represents a linear equation where T² is on the y-axis and l is on the x-axis:

        y = (4π² / g) l

The slope is given by:

         m = 4π² / g

Solving for g gives:

         g = 4π² / m

The slope is determined from the line's values rather than experimental data.

2) To perform the experiment, the string is secured to the sphere, then the pendulum length from the pivot to the sphere's center is measured using a tape measure. A slight angle (less than 10 degrees) is released, allowing the first swing to occur. Generally, the time for several oscillations, usually 10 or 20, is tracked to find the period:

    T = t / n

Next, a table is created comparing T² to the length, plotted with length on the x-axis to find the slope, from which the gravitational acceleration is derived.

3) The independent variable, which is the length of the pendulums, is plotted on the x-axis, while the dependent variable, the squared period, is on the y-axis.

4) Referring to the line equation:

            m = 4π² / g

             resulting in:

            g = 4π² / m

5) Once the spring is cut, the sphere continues to be influenced by gravitational acceleration. The harmonic motion ceases, and the sphere moves vertically.

5 0
1 month ago
You're driving your pickup truck around a curve that has a radius of 22 m.How fast can you drive around this curve before a stee
Sav [2230]

The maximum speed around this curve before a toolbox made of steel slips off the truck bed is: 14.832 m/s

Further explanation

The centripetal force acts on objects in circular motion, directed towards the circle's center.

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N

m = mass, Kg

v = linear velocity, m / s

r = radius, m

The velocity directed toward the center of the circle is referred to as linear velocity.

It can be represented as:

\displaysyle v = 2 \pi.r.f

r = radius of the circle

f = rotations per second (RPS)

Pickup trucks negotiating a curve are influenced by centripetal forces. To prevent the steel toolbox from slipping off the bed of the truck, the centripetal force acting on it must equal its weight. Should the centripetal force surpass the toolbox's weight, it will fall off.

centripetal force = weight

\rm \dfrac{mv^2}{r}=mg

Thus, the maximum velocity to keep the toolbox secure is:

\rm v^2=r\times g\\\\v=\sqrt{r\times g}

For a curve with a radius of 22 m, it follows that:

\rm v=\sqrt{22\times 10}\\\\v=\sqrt{220}\\\\v=\boxed{\bold{14.832\:m/s}}}

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The average velocity

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7 0
24 days ago
At a given location from a source charge, the electric field______________.a. strength is dependent on the source charge and the
Softa [2035]
b. The electric field diverges from the source charge when it is positive. d. If the source charge is negative, the electric field converges towards it. In more depth: A positive source charge generates an electric field that delivers a repulsion to a positively charged test charge. Hence, the field points outward from positively charged sources. Conversely, a positively charged test charge is drawn toward a negative source charge, resulting in electric field vectors consistently pointing towards negatively charged objects. Additionally, the intensity of the electric field solely depends on the test charge. Thus, the valid responses are b and d, confirming that the electric field points away from a positive source charge and toward a negative source charge.
3 0
19 days ago
If you accidentally touch the "hot" wire connected to the 120 V line, how much current will pass through your body?
serg [2598]

Complete Question:

Picture yourself on an aluminum ladder on the ground, attempting to fix an electrical connection with a metal screwdriver featuring a metallic handle. Since you are sweating profusely, your body has a resistance of 1.60 kΩ.

(a) If you accidentally contact the "hot" wire from the 120 V power line, what current will flow through your body?

(b) What is the amount of electrical power transferred to your body?

Answer:

(a) 0.075A

(b) 9W

Explanation:

According to Ohm's law, the voltage (V) applied to or passing through a body corresponds to the current (I) via the relationship:

V ∝ I

=> V = I x R                 ----------------------(i)

Where;

R denotes the resistance of the body

(a) As mentioned;

Due to wet conditions, the body will conduct electricity, and possesses the following values;

V = supplied voltage = 120V

R = resistance of the wet body = 1.60kΩ = 1.6 x 1000Ω = 1600Ω

Substituting these values into equation(i):

120 = I x 1600

To find I;

I = \frac{120}{1600}

I = 0.075A

Thus the current passing through your body is 0.075A

(b) Electrical power (P), which is expressed in Watts (W), delivered to the body is the product of current (I) and voltage (V) received. Thus:

P = I x V           ---------------------(ii)

Where;

I equates to 0.075A   [as derived above]

V is 120V     [as outlined in the question]

Plugging these values into equation (ii):

P = 0.075 x 120

P = 9W

Hence, the electrical power received by your body is 9W

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14 days ago
After soccer practice, Coach Miller goes to the roof of the school to retrieve the errant soccer balls. The height of the school
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Con una aceleración gravitacional de 9.8, una altura inicial de 3.5 m y una distancia de 22 m, la velocidad horizontal inicial es de 26.03 m/s y el tiempo de vuelo es de 0.845 segundos.
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