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MariettaO
18 days ago
13

2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind

Physics
1 answer:
Yuliya22 [2.4K]18 days ago
5 0

The speed resulting from the plane is (3) 226 m/s

Reasoning:

We can determine the plane's resultant speed using the Pythagorean Theorem because the two speeds form a right angle (creating a right triangle).

Thus, the computation is as follows:

ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}

ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}

Consequently, the plane's resultant speed is (3) 226 m/s

Have a wonderful day!

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(a) 29,905 m/s

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(b) 5.96\cdot 10^{-3} m/s^2

The centripetal acceleration that Earth experiences as it is drawn toward the sun is called radial acceleration:

a=\frac{v^2}{r}

where

v = 29,905 m/s is the orbital speed

r=1.50 \cdot 10^8 km = 1.50 \cdot 10^{11} m is the radius of the orbit

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a=\frac{(29,905 m/s)^2}{(1.50\cdot 10^{11} m)}=5.96\cdot 10^{-3} m/s^2

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For the planet Uranus, we can determine:

r=2.87 \cdot 10^9 km = 2.87 \cdot 10^{12} m is the radius of its orbit

T=84.02 y \cdot 365 d/y \cdot 24 h/d \cdot 60 min/h \cdot 60 s/min =2.65 \cdot 10^9 s is the time it takes for one complete orbit

Thus, the orbital speed is calculated as:

v=\frac{2\pi (2.87\cdot 10^{12} m)}{(2.65\cdot 10^9 s)}=6,801 m/s

(d) 1.61\cdot 10^{-5} m/s^2

For Uranus, with v = 6,801 m/s marking the orbital speed

r=2.87 \cdot 10^9 km = 2.87 \cdot 10^{12} m is the orbital radius

Thus, the radial acceleration can be expressed as:

a=\frac{(6,801 m/s)^2}{(2.87\cdot 10^{12} m)}=1.61\cdot 10^{-5} m/s^2

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