Response:
Magnitude of the electrostatic force acting on the +32 µC charge, 
Clarification:
Let q₁ = +32 µC, located at x₁ = 0
q₂ = +20 µC, positioned at x₂ = 40 cm = 0.4 m
q₃ = -60 µC, placed at x₃ = 60 cm = 0.6 m
Define the force magnitude on the +32 µC charge from the +20 µC charge as F₁ (the force on q₁ due to q₂).


Define the force magnitude on the +32 µC charge from the -60 µC charge as F₂ (the force on q₁ due to q₃).


The resultant electrostatic force on the 32 µC charge is 

The expected measurements should range as follows: 5, 10, 15, 20, and 25 meters.
Answer:

Explanation:
The measurement of pressure is indicated as
where p denotes the pressure,
signifies density, and h represents height
Given values include pressure
, gravity's acceleration
, and height =1.163 m

Answer:
The response to your inquiry is: 15 m/s²
Explanation:
Equation x = at³ - bt² + ct
a = 4.1 m/s³
b = 2.2 m/s²
c = 1.7 m/s
First we calculate x at t = 4.1 s
x = 4.1(4.1)³ - 2.2(4.1)² + 1.7(4.1)
x = 4.1(68.921) - 2.2(16.81) + 6.97
x = 282.58 - 36.98 + 6.98
x = 252.58 m
Now we calculate speed
v = x/t = 252.58/ 4.1 = 61.6 m/s
Finally
acceleration = v/t = 61.6/4.1 = 15 m/s²