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2 months ago

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Which of the following substances would release the most amount of heat when they cool from 50oC to 25oC if you started with equ

al masses of each?Aluminum, 0.920 J/goCCast iron, 0.461 J/goC or

1 answer:

lions [2.9K]2 months ago

3 0

Answer:

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Explanation:

c9yridutcltzojvifzlh ljf7gp please could you share the link for a moment 4

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Why the gross reading is needed when doing the titration?

Anarel [2989]

Answer:

The response is provided below.

Explanation:

Numerous aspects can influence the actual results of titration. These factors vary from human error to misjudging measurements, a researcher's interpretation of color changes, and improper techniques during the experimental procedure.

Thus, to mitigate these errors, researchers must engage thoroughly throughout experimentation, and employing gross readings can assist in reducing mistakes when determining the final titre value.

7 0

2 months ago

what is the net ionic equation with its physical states? (NH4)2CO3(aq)+Ca(ClO4)2(aq)⟶CaCO3(s)+2NH4ClO4(aq)

lions [2927]

Answer: The net ionic equation is $CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)$

Explanation:

A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.

$(NH_4)_2CO_3(aq)+Ca(ClO_4)_2(aq)\rightarrow CaCO_3(s)+2NH_4ClO_4(aq)$

The ion-based representation of the equation is:

$2NH_4^+(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2ClO_4^{-}(aq)\rightarrow CaCO_3(s)+2NH_4^{+}(aq)+2ClO_4^-(aq)$

"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.

Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.

Therefore, the net ionic equation is:

$CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)$

6 0

2 months ago

How much volume (in cm3) is gained by a person who gains 11.1 lbs of pure fat?

Anarel [2989]

The density of human fat is $0.918 g/cm^{3}$ . The mass of the pure fat is 11.1 lbs.

First, convert the mass from pounds to grams as follows:

1 lb=453.592 g

Thus,

$11.1 lb\rightarrow 11.1\times 453.592 g=5034.875 g$

Density is defined as mass per unit volume, meaning volume can be calculated as:

$V=\frac{m}{d}$

By substituting the values,

$V=\frac{5034.875 g}{0.918 g/cm^{3}}=5484.61 cm^{3}$

Consequently, the volume gained by the individual will be $5484.61 cm^{3}$ .

6 0

2 months ago

The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr

lions [2927]

Response:

The pKa value is 13.0.

Clarification:

pKa + pKb = 14

For trimethylamine, Kb = 6.3 × $10^{-5}$

Calculating pKb: pKb = - log (6.3 × $10^{-5}$ )

= 1.0

Thus, pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Verification: The typical range for pKa in weak acids is from 2 to 13.

8 0

2 months ago