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geniusboy
3 months ago
11

Two experiments are performed on an object to determine how much the object resists a change in its state of motion while at res

t and while in motion. In the first experiment, the object is pushed with a constant known force along a horizontal surface. There is negligible friction between the surface and the object. A motion sensor is used to measure the speed of the object as it is pushed. In a second experiment, the object is tied to a string and pulled upward with a constant known force, and a motion sensor is used to measure the speed of the object as it is pulled upward. The student uses the data collected from the motion sensor to determine the mass of the object in both experiments.
Required:
What classifies the type of mass that was determined in each experiment?
Physics
1 answer:
inna [3.1K]3 months ago
5 0

Answer:

The first experiment measures inertial mass, while the second experiment measures gravitational mass.

Explanation:

A student conducts two different experiments to observe resistance to changes in motion, both when at rest and in motion.

In the initial experiment, an object is forcefully pushed against a flat surface while its speed is tracked by a sensor. This setup involves work done against the object's inertia, identifying the mass as inertial mass.

Conversely, in the subsequent experiment, the object is lifted or thrown upward with an applied force and the speed is recorded. Here, the mass refers to gravitational mass, as the work performed combats gravity or the object's weight.

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Complete Question

A 30 cm cm wrench is employed to loosen a bolt, with force applied 0.30m from the bolt. It requires 60 N to loosen the bolt when force is applied perpendicular to the wrench. How much force would be necessary if the force were applied at a 30-degree angle from perpendicular?

Response:

The strength needed is F_{\theta } = 69.28 \ N

Clarification:

According to the problem, we know that

    The length of the wrench is L = 30 cm = \frac{30}{100} = 0.3 \ m

    The distance from the bolt is  d = 0.30 m

      The force necessary to loosen the bolt is F = 60 N

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Generally, the torque required for loosening the bolt is defined as

       \tau = F * d

        \tau = 60 * 0.3

        \tau = 18 Nm

Now for the bolt to loosen at \theta the torque at 90° must equal that at \theta

Thus, the torque at \theta is represented mathematically as

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substituting values gives us

           18 = F_{\theta } * 0.3 cos (30)

           F_{\theta } = \frac{18}{0.3 cos (30)}

           F_{\theta } = 69.28 \ N

       

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Answer:

The answer to the specified question will be "\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}".

Explanation:

Referring to the question,

\sum F_{x}

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Now,

From equation 1 and equation 2, we conclude

⇒  T_{m} Cos \theta = \mu_{s}F_{N}

By substituting the value of F_{N}, we derive

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⇒  \mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}

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