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3 months ago

5

Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.

F > Cl > Br > I
Br2 + NaF Right arrow.

no reaction
Na + FBr2
NaBr + F2
Na2F + Br2

2 answers:

ValentinkaMS [3.4K]3 months ago

7 0

Response: The result would be no reaction.

Clarification:

Softa [3K]3 months ago

6 0

Response:

A.) no reaction. Edge 2020.

Clarification:

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3 months ago

A uniformly charged spherical droplet of mercury has electric potential Vbig throughout the droplet. The droplet then breaks int

kicyunya [3294]

Answer:

$\frac{V_{big}}{V_{small}} = n^{2/3}$

Explanation:

Let the charge on the large droplet be denoted as Q.

When the radius of the droplet is R, the electric potential for the larger droplet can be expressed as:

$V_{big} = \frac{KQ}{R}$

If it splits into n identical droplets, let the charge of each be "q" and their radius be "r".

Applying volume conservation gives us:

$\frac{4}{3}\pi R^3 = n(\frac{4}{3}\pi r^3)$

$r = \frac{R}{n^{1/3}}$

Now, the potential for the smaller droplets is given as:

$V_{small} = \frac{kq}{r}$

$V_{small} = \frac{K(Q/n)}{\frac{R}{n^{1/3}}}$

$V_{small} = \frac{1}{n^{2/3}}\frac{KQ}{R}$

$\frac{V_{big}}{V_{small}} = n^{2/3}$

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3 months ago