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9 days ago

5

Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.

F > Cl > Br > I
Br2 + NaF Right arrow.

no reaction
Na + FBr2
NaBr + F2
Na2F + Br2

2 answers:

ValentinkaMS [2.4K]9 days ago

7 0

Response: The result would be no reaction.

Clarification:

Softa [2K]9 days ago

6 0

Response:

A.) no reaction. Edge 2020.

Clarification:

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Clarification:

According to the work-energy principle, the task performed on an object corresponds to the alteration in its kinetic energy. In mathematical terms:

$W=K_f -K_i= \Delta K$

where:

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$K_i$ indicates the kinetic energy at the start

Furthermore, when the force is exerted in line with the object’s motion, the work done is expressed as:

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Here,

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In this scenario, the force impacting the object is

F

While the distance moved is the horizontal length traveled, hence

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Learn more about work and kinetic energy:

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14 days ago

An aluminum rod is 10.0 cm long and a steel rod is 80.0 cm long when both rods are at a temperature of 15°C. Both rods have the

serg [2593]

Response:

0.9 cm

Clarification:

The following illustrates the calculation of the combined rod's length increase:

As established

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We simply summed the expansions of both the aluminum and steel rods to determine the overall increase in the joined rod's length, which must be factored in

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A positive point charge q is placed at the center of an uncharged metal sphere insulated from the ground. The outside of the sph

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3 days ago

If Pete ( mass=90.0kg) weights himself and finds that he weighs 30.0 pounds, how far away from the surface of the earth is he

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The answer is 9938.8 km. Explanation: 1 pound-force = 4.48 N. Hence, 30.0 pounds-force = 134.4 N. The gravitational force between Earth and an object on its surface is defined by: Where M denotes Earth’s mass, m is the object's mass, and R represents the Earth's radius (6371 km). To determine height (h) above Earth's surface, we compare ratios. Ultimately, Pete's weight would be 30 pounds at a height of 9938.8 km from the Earth's surface.

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8 days ago

A spin bike has a flywheel in two parts—a 12.5 kg disk with radius 0.23 m, and a 7.0 kg ring with mass concentrated at the outer

Keith_Richards [2256]

Response:

Clarification:

Provided

weight of disk $m=12.5 kg$

diameter of disc $R=0.23 m$

weight of ring $m_r=7 kg$

Force $F=9.7 N$

$N=180 rpm$

$\omega =\frac{2\pi N}{60}$

$\omega =6\pi rad/s$

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=Disc's moment of inertia +Ring's Moment of Inertia

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At this point, Torque is $T=F\times R=I\cdot \alpha$

$9.7\times 0.23=0.7\times \alpha$

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Utilizing $\omega _f=\omega +\alpha t$

$\omega _f=0$ in this scenario

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$t=5.92 s$

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1 day ago