Answer:
Acceleration(a) = 0.75 m/s²
Explanation:
Given:
Force(F) = 3 N
Mass of object(m) = 4 kg
Find:
Acceleration(a)
Computation:
Force(F) = ma
3 = (4)(a)
Acceleration(a) = 3/4
Acceleration(a) = 0.75 m/s²
Solution:
/ Em₀ = 0.30
Explanation:
In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.
K = ½ m v²
U = mgh
We assess the mechanical energy at two positions:
Initial. Lower
Em₀ = K = ½ m v²
At its highest point
= U = mg and
Now let's compute
Em₀ = ½ m 3.6²
Em₀ = m 6.48
= m 9.8 × 0.2
= m 1.96
Thus the energy lost is given by:
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
This means that 30% of the sun's energy is transformed into potential energy.
There are various conversion possibilities.
This energy changes into thermal energy affecting the spores and air, since it cannot be regained.
Energy can be determined using the formula power multiplied by time, thus for a power of 1200 W (or 1200 Joules per second) and a duration of 30 seconds, the calculation yields 36000 J or 36 kJ of electrical energy.
If you need the electrical charge or current: Power equals voltage times current. Therefore, with a power of 1200 watts and a voltage of 120 V, the current can be found as 1200 W divided by 120 V, which results in 10 Amperes. The charge is obtained by multiplying 10 A by 30 s, yielding 300 C.
Explanation:
The term 'collision' refers to the interaction between two objects. There are two distinct types of collisions: elastic and inelastic.
In this scenario, two identical carts are heading towards each other at the same speed, resulting in a collision. In an inelastic collision, the momentum is conserved before and after the incident, but kinetic energy is lost.
After the event, both objects combine and move together at a single velocity.
The graph representing a perfectly inelastic collision is attached, illustrating that both carts move together at the same speed afterward.
Answer:3.87*10^-4
Explanation:
To determine the mass reduction, delta mass Xe, of the xenon nucleus due to its decay, we first use the provided wavelength of the gamma radiation to calculate its frequency via c = freq*wavelength.
From C=f*lambda we set up: 3*10^8=f*3.44*10^-12.
Solving gives frequency F=0.87*10^20 Hz.
Next, we calculate the emitted energy using the equation E=hf, which translates to E=f*Planck's constant.
Thus, E=0.87*10^20*6.62*10^-34, resulting in E=575.94*10^(-16).
This energy is then converted from joules to MeV.
Utilizing the formula E=mc^2, with c^2 = 931.5 MeV/u, enables us to find the reduction in mass, yielding
3.87*10^-4 u.