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1 month ago

A large insulating sheet has a surface charge density σ. what is the electric field strength near the insulating sheet?

1 answer:

3 0

The only scenarios where one can derive dependable data from a noncontact measurement of an insulator's charge state are with free insulative sheets or those that have a grounded conductor backing. In each of these instances, the electric field generated by the charge plays a crucial role.

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Uzupełnij zdania właściwymi sformułowaniami. Wyobraź sobie, że między linę a siodełko karuzeli łańcuchowej wmontowany jest siłom

ValentinkaMS [3360]

Explanation:

Here’s a revised version of the requirements;

Fill in the blanks with the appropriate terms. Picture a force gauge fixed between the rope and the saddle of the chain carousel. If you keep your feet off the ground while the vehicle is not in motion, the dynamometer shows A / B. When the carousel is spinning, you’ll see C / D displayed on the dynamometer.

A. Your weight including the saddle

C. Value of the rope's strength

B. Your weight

D. Value of the centripetal force

3 0

1 month ago

In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c

Sav [3045]

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

$GDP=\pi } \frac{d^{2} }{4}$

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

$GDP_{b} =\pi \frac{3^{2} }{4}$

Conversely, in darkness, the diameter typically enlarges to 7 mm.

$GDP_{b} =\pi \frac{7^{2} }{4}$

This indicates an increase in light-gathering capacity.

$Increase=\pi \frac{49}{4} -\pi \frac{9}{4} \\Increase=31.4 mm^{2}$

Thus, the amount of light the eye can capture is 31.4 mm².

3 0

1 month ago

Compare the time period of two simple pendulums of length 4m and 16m at a place.

Ostrovityanka [3082]

Answer:

The period of the pendulum measuring 16 m is double that of the 4 m pendulum.

Explanation:

Recall that the period (T) of a pendulum with length (L) is defined by:

$T=2\,\pi\,\sqrt{ \frac{L}{g} }$

where "g" denotes the local gravitational acceleration.

Since both pendulums are positioned at the same location, the value of "g" will be consistent for both, and when we compare the periods, we find:

$T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2$

Thus, the duration of the 16 m pendulum is two times that of the 4 m one.

5 0

1 month ago

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame

kicyunya [3162]

For motion in a circle.

Centripetal acceleration is calculated as mv²/r = mω²r

where v represents linear velocity, r equals radius which is diameter/2 equating to 1/2 or 0.5m

. Here, m is the mass of the object, which is 175g or 0.175kg.

The angular speed, ω, is derived from Angle covered / time

   = 2 revolutions per 1 second

   = 2 * 2π radians for each second

   = 4π radians per second

Thus, Centripetal Acceleration = mω²r = 0.175*(4π)² * 0.5. Utilize a calculator

   ≈13.817 m/s²

. The acceleration's magnitude is approximately 13.817 m/s² and it is oriented towards the center of the circular path.

The tension in the string equates to m*a

   = 0.175*13.817

   = 2.418 N

5 0

17 days ago

Read 2 more answers

A parachutist, after opening her parachute, finds herself gently floating downward, no longer gaining speed. She feels the upwar

Sav [3045]

As the parachutist is descending at a steady rate

we can conclude that

$a = \frac{dv}{dt}$