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valkas
2 months ago
13

A large insulating sheet has a surface charge density σ. what is the electric field strength near the insulating sheet?

Physics
1 answer:
Ostrovityanka [3.2K]2 months ago
3 0
The only scenarios where one can derive dependable data from a noncontact measurement of an insulator's charge state are with free insulative sheets or those that have a grounded conductor backing. In each of these instances, the electric field generated by the charge plays a crucial role.
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In 1610, galileo used his telescope to discover four prominent moons around jupiter. their mean orbital radii a and periods t ar
Yuliya22 [3333]
The time period for any moon of Jupiter is described by the formula above, which also allows us to calculate Jupiter's mass. For part a, T is 1.77 days, which is equal to 152928 seconds. Applying the formula, we can derive the values needed. For part B, T equals 3.55 days or 306720 seconds, and repeating this with the necessary formula allows us to find the mass of Jupiter. For part c, T is 7.16 days, equating to 618624 seconds. Once again, using the earlier formula, we find Jupiter's mass. Finally, for PART D, T is noted to be 16.7 days or 1442880 seconds, and we can find the mass of Jupiter using the provided formula.
6 0
2 months ago
A wire has an electric field of 6.2 V/m and carries a current density of 2.4 x 108 A/m2. What is its resistivity
Softa [3030]

Response:

The resistivity can be expressed as \rho = 2.5 *10^{-8} \ \Omega \cdot m

Clarification:

According to the information provided,

    The value of the electric field measures  E = 6.2 V/m

     The density of current is given as  J = 2.4 *10^{8} \ A/m^2

Typically, resistivity is represented in mathematical terms as

         \rho = \frac{E}{J}

by inserting values

        \rho = \frac{6.2}{2.4 *10^{8}}

        \rho = 2.5 *10^{-8} \ \Omega \cdot m

5 0
1 month ago
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