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son4ous
3 months ago
11

The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one imp

ortant model is missing.
An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle.

Which atomic model is missing from this set?

Bohr’s model
Dalton’s model
Rutherford’s model
Thomson’s model

Physics
2 answers:
Maru [3.3K]3 months ago
8 0

Answer:

Dalton's model... I completed the test!

Explanation:

Maru [3.3K]3 months ago
4 0

Answer: Dalton’s model

Explanation:

The image provided depicts four atomic models, each marked with a letter:

W corresponds to the current widely accepted atomic model: a nucleus surrounded by an electron cloud, where the positions and orbits of electrons around the nucleus are defined by regions (linked to specific energy levels) where the probability of finding an electron is highest. It's key to note that this model was refined through the contributions of quantum physics by Louis de Broglie and Erwin Schrodinger.

X refers to Rutherford's model (developed after Thomson's model). Ernest Rutherford conducted experiments that confirmed Thomas's atomic theory. Yet, the results led him to discover that there was a core of charge in the atom (later termed the nucleus) surrounded by electrons. Thus, a new atomic model was introduced, showcasing a positively charged nucleus enveloped by negatively charged electrons, resembling the solar system.

Y denotes Thomson's model, often called the plum pudding model. This scientist identified that atoms include smaller charged particles, defined as electrons. At that point, without knowledge of the atomic nucleus, Thomson theorized that electrons floated in a positively charged substance that balanced the negative charge of the electrons, similar to raisins in pudding or bread.

Z symbolizes Bohr's model. Proposed by Danish physicist Niels Bohr after Rutherford's findings, this model incorporates Rutherford’s concept but adds that electrons travel in specific orbits around the nucleus at varying energy levels.

Hence, the absent model is Dalton's model, recognized as the first atomic model: the atom visualized as an indivisible, solid sphere. This was a generally accepted notion at the time, dating back to ancient Greek philosophy.

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inna [3103]

The new charge of the ball will amount to 8x10^8C after removing 5x10^27 electrons.

Explanation:

Initially, if the sphere is electrically neutral, its charge stands at 0C.

When an electron with a charge of (-1.6*10^-19 C) is taken away, we effectively add a positive charge, leading to:

1.6*10^-19 C as the sphere's new charge.

For a total of N electrons removed, the sphere's overall charge now becomes:

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To calculate N when:

N*1.6*10^-19 C = 8.0x 10^8 C.

We find that N is: (8.0/1.6)x10^(8 + 19) = 5x10^27 electrons.

7 0
4 months ago
A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0. Wha
serg [3582]

Answer:

a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

Explanation:

Data provided

initial velocity v₀=20 cm/s at time t=3s

final velocity vf=0 at time t=8 s

Required

Average Acceleration for the interval from 3s to 8s

Solution

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a_{acceleriation} =\frac{dv_{velocity}}{dt_{time}}\\a_{acceleriation} =\frac{v_{f}-v_{o} }{dt}\\ a_{acceleriation} =\frac{0-20cm/s }{8s-3s}\\ a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

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<span>To solve, utilize F=(K*Q1*Q2)/r^2 </span>
<span>You'll want to equate F with the drag force, where the electric field strength translates to (K*Q2)/r^2; substituting the values results in </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
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