Answer:
σ₁ =
C/m²
σ₂ =
C/m²
Explanation:
Provided Information:
i) Smaller sphere's radius ( r ) = 5 cm.
ii) Larger sphere's radius ( R ) = 12 cm.
iii) Electric field at the larger sphere's surface ( E₁ ) = 358 kV/m, which is equivalent to 358 * 1000 v/m


Charge (Q₁) = 572.8
C
Since the electric field inside a conductor is zero, the electric potential ( V ) remains constant.
V = constant
∴

=
C
Surface charge density ( σ₁ ) for the larger sphere.
Calculated Area ( A₁ ) = 4 * π * R² = 4 * 3.14 * 0.12 = 0.180864 m².
σ₁ =
=
=
C/m².
Surface charge density ( σ₂ ) for the smaller sphere.
Calculated Area ( A₂ ) = 4 * π * r² = 4 * 3.14 * 0.05² = 0.0314 m².
σ₂ =
=
=
C/m²
A) B) Explanation: Given: temperature of air, temperature of lungs, specific heat transferred from the lungs, specific heat of air, mass of 1 L air, breath rate. A) Calculate the amount of heat required to raise the air in the lungs to body temperature. B) Determine heat loss per hour.