Response: The moles in 369 grams of calcium hydroxide are 4.98 moles
Reasoning: Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used:
Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.
Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
The formula for a monoprotic acid can be represented as HA, and its reaction with a base is shown as follows: HA + NaOH ---> NaA + H₂O. The stoichiometry between the acid and the base is 1:1. At the point of neutralization, the moles of HA equals the moles of the base. The moles of NaOH that reacted can be calculated as 0.100M / 1000 mL/L x 30.0 mL = 0.003 mol. Consequently, the moles of HA that reacted equal 0.003 mol. The mass of the acid is 0.384 g, yielding a molar mass of 0.384 g / 0.003 mol = 128 g/mol.
Answer: Reaction 2 is a spontaneous one.
Explanation:
According to our understanding:
= +ve, meaning the reaction is non-spontaneous
= -ve, indicating the reaction is spontaneous
= 0, stating that the reaction is at equilibrium
For a reaction to be classified as spontaneous, the Gibbs free energy must yield a negative value.
Reaction 1:
Glucose + Pi ⟶ glucose-6-phosphate + H₂O, ΔG = +13.8 kJ/mol
Reaction 2:
ATP + H₂O ⟶ ADP + Pi, ΔG = -30.5 kJ/mol
From this, we can conclude that ΔG being negative indicates that reaction 2 is indeed spontaneous.
