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Karolina
2 months ago
12

The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of ca

lcium carbonate are needed to provide the rda of calcium?
Chemistry
2 answers:
VMariaS [2.9K]2 months ago
6 0

Answer:

To meet the daily calcium requirement, 10 grams of calcium carbonate is essential.

Explanation:

The daily calcium requirement (RDA) is equal to 1.2 grams.

Calcium carbonate has a calcium mass percentage of 12.0%.

Let x be the total mass of calcium carbonate.

\%=\frac{\text{Mass of an element}}{\text{Total mass of compound}}\times 100

12.0\%=\frac{1.2 g}{x}\times 100

x = 10 g

10 grams of calcium carbonate is needed to fulfill the calcium RDA.

eduard [2.7K]2 months ago
4 0
1) Calcium carbonate comprises 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (which is 40.0%)!

2) The mass fraction mentioned is superfluous information.

3) The resulting solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
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