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GenaCL600
27 days ago
8

In the compound k[co(c2o4)2(h2o)2] (where c2o42– = oxalate) the oxidation number and coordination number of cobalt are, respecti

vely
Chemistry
2 answers:
Anarel [2.6K]27 days ago
8 0

Answer:

Oxidation number: +3

Coordination number: 4

Explanation:

In K[Co(C₂O₄)₂(H₂O)₂], with C₂O₄²⁻ being oxalate, what are the oxidation and coordination numbers for Cobalt?

The overall charge equals the sum of charges and oxidation states of all components, which totals to zero here.

K + Co + 2. C₂O₄²⁻ + 2. H₂O = 0

+1 + Co + 2. (2-) + 2. 0 = 0

Co = +3

The coordination number refers to the total number of ligands directly bonded to the central metal. Since cobalt is bonded to 2 oxalate ions and 2 water molecules, the coordination number amounts to 2 + 2 = 4.

castortr0y [2.7K]27 days ago
6 0
Let's represent molecules with symbols as follows:

                   C₂O₄  =  X
and
                    H₂O  =  Y
Then,
                                K [ Co (X)₂ (Y)₂ ]

Since Potassium (K) has an oxidation number of +1

To achieve neutrality, the oxidation number of the coordination sphere needs to equal -1.
Thus,
                                    [ Co (X)₂ (Y)₂ ]  =  -1
Given that,
           the O.N of X is -2
Therefore,
       O.N of (X)₂ equals -4

Additionally,
O.N of H₂O is zero since it remains neutral. Therefore,

                                    [Co - 4 + 0 ]  =  -1
Or,
                                    Co  =  -1 + 4

                                    Co  =  +3

Conclusion:
          The oxidation number for the coordination sphere is -1, and the oxidation state of copper is +3.
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Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

v_d=\frac{I}{neA}

where

I stands for current

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e=1.6\cdot 10^{-19}C indicates the charge of an electron

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2)

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N'=8\cdot 10^9

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