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kupik
17 days ago
8

Check all the boxes that describe the electron sea model. It is the simplest metal bonding model. It is the most complicated met

al bonding model. Metallic bonding results from the transfer of valence electrons. Metallic bonding results from the sharing of valence electrons. The electrons are delocalized. The electrons are attracted to specific nuclei. The delocalized electrons serve as the glue that keeps the metal atoms together. The electrons that are attracted to specific nuclei serve as the glue that keeps the metal atoms together.
Chemistry
2 answers:
Alekssandra [2.7K]17 days ago
8 0
1st option 4th option 5th option 7th option Those are the correct selections.
lions [2.6K]17 days ago
3 0
Another interpretation can be drawn from this definition: (Electron Sea Model): Metallic bonds are formed from a collection of metal atoms that have all contributed their valence electrons into an electron cloud that fills the entire structure. This cloud of electrons is often called an electron sea. To visualize the electron sea model, you might consider it like a box of marbles floating in water; the marbles signify the metal atoms while the water embodies the electron sea.
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The ions Ca2+ and PO43- form salt with the formula
Alekssandra [2711]

Ca3(PO4)2 is the correct formula.

7 0
20 days ago
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The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c
castortr0y [2743]

Answer:- 0.134 seconds

Solution:- The speed is given as 2.988*10^8\frac{m}{s} and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.

Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, 24900mile(\frac{1609.34meter}{mile})

= 40072566 meters

Now, speed=\frac{distance}{time}

Rearranged for time, that gives: time=\frac{distance}{speed}

Inserting the values:

time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}

= 0.134 seconds

Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.

8 0
1 month ago
A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
KiRa [2711]

Response:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Clarification:

Weight of the alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Weight of the water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

Using the energy balance equation,

Heat released by the alloy = Heat absorbed by the water

m_{a} C_{a} [[T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This gives us the specific heat of the alloy.

4 0
1 month ago
The table lists the lattice energies of some compounds. Compound Lattice Energy (kJ/mol) LiF –1,036 LiCl –853 NaF –923 KF –821 N
KiRa [2711]

Response: Option A) The lattice energy rises as cations become smaller, as demonstrated by LiF and KF.

Clarification: It has been observed that the lattice energy is largely determined by two primary factors regarding ionic solids:

i) The ionic charges - An increase in the charge of the ions corresponds to an increase in lattice energy.

and

ii) The size or radius of the ions - As the ionic size grows, the lattice energy diminishes accordingly.

Therefore, in this context, the latter factor is evident. Thus, it can be concluded that as cation sizes decrease among ionic solids, the lattice energy increases.

7 0
9 days ago
Read 2 more answers
Why would it be better to be an r-selected species if the water resources in an area were to become more limited over a short pe
lions [2653]
An r-selected species has a significantly faster reproductive rate compared to K-selected species.

The focus of r-selected species is on quick maturation and reproduction. They are likely to breed during short periods when water supply is available, thus enhancing their survival chances.

Conversely, K-selected species prioritize nurturing their young and tend to reproduce later. Due to the longer maturation time before breeding, by the time K-selected species are ready, the water supply may be depleted, leading to lower survival odds.

Hope this clarifies!
If you have more questions, don’t hesitate to ask! Have a fantastic day!:)

~Collinjun0827, Junior Moderator
6 0
17 days ago
Read 2 more answers
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