Answer:
Protons: 19
Neutrons: 25
Electrons: 19
Explanation:
Protons:
The atomic number determines the number of protons in an atom. Consequently, with Potassium's atomic number being 19, it contains 19 protons.
Neutrons:
The formula to find neutrons is:
# of Neutrons = Atomic Mass - # of Protons
Given:
Atomic Mass = 43
# of Protons = 19
Thus,
# of Neutrons = 43 - 19
# of Neutrons = 24
Electrons:
In a neutral atom, the quantity of electrons matches that of protons. Therefore, a neutral Potassium atom with 19 protons must equally have 19 electrons.
Answer:
(A) It can be a fundamentally arbitrary process.
Explanation:
In various human disorders, the natural process of protein folding may malfunction, generally beginning with the formation of a very compact state. This process may also include a systematic decrease in the variety of conformational states and the initial creation of localized structures. Thus, option (A) is the only incorrect statement.
Noble gas notation serves as a condensed form of indicating electron configurations. This notation employs the symbol for the preceding noble gas in the electron configuration of an element. For antimony, the noble gas prior is Kr, which means Xe is not used in its electron configuration. Similarly, for radium, the prior noble gas is Rn, whereas, for uranium, it is also Rn. However, for cesium, the preceding noble gas is Xe, thus it is utilized in the noble gas notation for Sb, specifically written as: Cs: [Xe] 6s.
Answer: cesium
Answer:
Please review the following responses
Explanation:
1) A solution of 100. mL contains 19.5 g of NaCl (3.3M)
2) 100. mL of NaCl solution at 3.00 M (3 M)
3) A solution of 150. mL holds 19.5 g of NaCl (2.2 M)
4) The concentrations of beakers 1 and 5 are identical (1.5M)
Molar mass of NaCl = 23 + 36 = 59 g
For beaker number 3:
59 g -------------- 1 mol
19.5 g ------------- x
x = 19.5 x 1/59 = 0.33 mol
Molarity (M) = 0.33 mol/0.150 l = 2.2 M
For beaker number 4:
Molarity (M) = 0.33mol/0.10 l = 3.3 M
For beaker number 5:
Molarity (M) = 0.450/0.3 = 1.5 M