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nirvana33
27 days ago
15

What acid chloride would be needed to prepare the following ketone from benzene using a Friedel-Crafts acylation? Click the "dra

w structure" button to launch the drawing utility.

Chemistry
1 answer:
alisha [2.7K]27 days ago
3 0

Answer:

                    Benzoyl Chloride

Explanation:

                     Friedel-Craft Acylation is a reaction used to incorporate electrophiles (especially carbonyl groups) into the double bonds of aromatic compounds.

This scenario involves synthesizing benzophenone using benzene and benzoyl chloride.

Mechanism:

Step 1: Initially, benzoyl chloride reacts with a Lewis acid to create an electrophile known as oxo(phenyl)methylium.

Step 2: The second stage involves benzene participating in an electrophilic substitution reaction, where the electrophile is added.

Step 3: Finally, the aromatic nature of benzene is restored by releasing a proton.

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20 days ago
During which time interval does the substance exist as both a liquid and a solid
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1 month ago
The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c
castortr0y [2743]

Answer:- 0.134 seconds

Solution:- The speed is given as 2.988*10^8\frac{m}{s} and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.

Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, 24900mile(\frac{1609.34meter}{mile})

= 40072566 meters

Now, speed=\frac{distance}{time}

Rearranged for time, that gives: time=\frac{distance}{speed}

Inserting the values:

time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}

= 0.134 seconds

Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.

8 0
1 month ago
A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
KiRa [2711]

Response:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Clarification:

Weight of the alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Weight of the water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

Using the energy balance equation,

Heat released by the alloy = Heat absorbed by the water

m_{a} C_{a} [[T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This gives us the specific heat of the alloy.

4 0
1 month ago
What is the density (in g/L) of a gas with a molar mass of 16.01 g/mol at 1.75 ATM and 337 K?
Anarel [2600]
To solve for density, you can use the formula--> Density= PM/ RT, where P stands for pressure, M for molar mass, R represents the gas constant, and T is temperature. 

P= 1.75 atm
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R= 0.0821 atm·L/ mol·K
T=337 k

Thus, the density calculation becomes: density= (1.75 x 16.01)/ (0.0821 x 337)= 1.01 g/L
8 0
9 days ago
Read 2 more answers
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