Answer:
The solution to your inquiry is C = 0.000333 kcal/g°C
or C = 0.333 cal/g°C
Explanation:
Data
Q = 1.67 kcal
mass = 79.2 g
ΔT = 63.3°C
Formula
Q = mCΔT
Solving for C
C = Q/mΔT
Substituting values
C = 1.67/(79.2 x 63.3)
Simplifying
C = 1.67 / 5013.4
Final Result
C = 0.000333 kcal/g°C
or C = 0.333 cal/g°C
The density of human fat is
. The mass of the pure fat is 11.1 lbs.
First, convert the mass from pounds to grams as follows:
1 lb=453.592 g
Thus,

Density is defined as mass per unit volume, meaning volume can be calculated as:

By substituting the values,

Consequently, the volume gained by the individual will be
.
Answer:
The correct options include choice 2, 3, and 6.
Explanation:
Density is identified as the mass of a substance per unit volume occupied by that substance.

The density remains constant for a given substance, regardless of variations in mass and volume hence it is considered an intensive property.
2. 20.2 g of silver in 21.6 mL of water and 12.0 g of silver also in 21.6 mL of water.
3. 15.2 g of copper in 21.6 mL of water and 50.0 g of copper in 23.4 mL of water.
6. 11.2 g of gold in 21.6 mL of water and 14.9 g of gold in 23.4 mL of water.
The same metals in both instances will yield consistent densities due to the fixed density of the metal.
Answer:
Complete Question:
Equimolar quantities of CH3OH(l) and C2H5OH(l) are placed in separate 2.0 L containers that have been evacuated beforehand. Pressure gauges are attached to each container, and the temperature is maintained at 300 K. In both containers, liquid is consistently visible at the bottom. The varying pressure within the vessel that contains CH3OH(l) is illustrated below.
In comparison to the equilibrium vapor pressure of CH3OH(l) at 300 K, the equilibrium vapor pressure of C2H5OH(l) at 300 K is
ANSWER : lower, since the London dispersion forces among C2H5OH molecules surpass those among CH3OH molecules.
Explanation:
To clarify the answer provided, let’s begin by defining some concepts.
The London dispersion force is the least strong type of intermolecular force. It is a temporary force that arises when the electron arrangement in two neighboring atoms creates transient dipoles.
The vapor pressure of a liquid reflects the equilibrium pressure of its vapor above the liquid (or solid); specifically, it represents the pressure associated with the evaporation of a liquid (or solid) in a sealed environment above the substance.
The pressure will be lower due to the stronger London dispersion forces acting between C2H5OH molecules compared to those between CH3OH molecules. This implies that when intermolecular forces are stronger, they intensify the interactions binding the substance together, thereby reducing the liquid's vapor pressure at any given temperature and making it more difficult to vaporize the substance.
Note: The London dispersion force for C2H5OH is more substantial than for CH3OH because C2H5OH has more electrons than CH3OH.
Respuesta:
0.16 M
Explicación:
Teniendo en cuenta:

O sea,

Dado que:
Para
:
Molaridad = 0.200 M
Volumen = 20.0 mL
Convierte mL a L:
1 mL = 10⁻³ L
Entonces, volumen = 20.0×10⁻³ L
Los moles de
son:

Moles de
= 0.004 moles
Para
:
Molaridad = 0.400 M
Volumen = 30.0 mL
Convertimos mL a L:
1 mL = 10⁻³ L
Volumen = 30.0×10⁻³ L
Entonces, los moles de
son:

Moles de
= 0.012 moles
Según la reacción:

1 mol de
reacciona con 1 mol de 
Por lo tanto,
0.012 mol de
reacciona con 0.012 mol de 
Moles disponibles de
= 0.004 mol
El reactivo limitante es el que está en menor cantidad, entonces
es el limitante (0.004 < 0.012).
La formación del producto depende del reactivo limitante, así que,
1 mol de
reacciona con 1 mol de
y produce 1 mol de 
0.004 mol de
reacciona con 0.004 mol de
y genera 0.004 mol de 
Los moles restantes de
son: 0.012 - 0.004 = 0.008 mol
El volumen total es 20 + 30 mL = 50 mL = 0.050 L
Por lo que la concentración del ion bario,
, después de la reacción es:
