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astra-53
17 days ago
7

In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t

rip took about 22 days, and the fish consumed energy at a rate of 2.0 W for each kilogram of body mass. Part A What is the total energy used by a 2.0-kg salmon while making this 22-day trip?
Physics
1 answer:
Keith_Richards [2.2K]17 days ago
6 0

Answer:

E_t_o_t_a_l=7.603MJ

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, W, is linked to its specific mechanical power. Mechanical \ power calculated per unit mass can be derived from the following equation:

\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

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Calculate the heat required when 2.50 mol of a reacts with excess b and a2b according to the reaction: 2a + b + a2b → 2ab + a2 g
Softa [2035]

Answer:

Q = 12.5 kJ

Explanation:

The formula used to compute heat is:

Q = H° * n

Where:

Q: heat (J or kJ)

H°: enthalpy of reaction (kJ/mol)

n: moles

Now, as noted in the comments, the question lacks completeness, here is the part that is missing:

Given:

2A + B  A2B (1)

ΔH° = – 25.0 kJ/mol

2A2B  2AB + A2 (2)

ΔH° = 35.0 kJ/mol

Using these two reactions, we can determine the heat change.

Using the above two reactions, we need to establish the overall reaction (the one presented in the question), so let’s combine (1) and (2):

2A + B -------> A2B   H°1 = -25 kJ/mol

2A2B --------> 2AB + A2   H°2 = 35 kJ/mol

When we add these equations, one A2B cancels out with one A2B from reaction 2, thus, we have:

2A + B + 2A2B -------> 2AB + A2

So, for the enthalpy, the values are summed:

H°3 = -25 + 35 = 10 kJ/mol

Now we can calculate the heat:

Q = 10 * 2.5 = 25 kJ

However, as we have 2A in the reaction, it does not maintain a 1:1 mole ratio, instead, it is 1:2, which requires us to adjust; thus:

Q = 25 / 2 = 12.5 kJ

3 0
8 days ago
myron is almost late for class and he is running quickly to arrive before the professor begins lecturing as he listen to the pro
inna [2210]
No established theory exists here.
Myron has presented a strong hypothesis to clarify his observations.
Alternative hypotheses could be:

-- An infected mosquito might have bitten him during his sleep, causing symptoms to manifest.

-- He may have consumed something for dinner that was a bit spoiled.

-- He might have had excessive alcohol at the fraternity party last night.

-- The air in the classroom could contain elevated levels of Carbon Dioxide.

-- His body might be responding to the physical exertion of rushing to class.

Currently, Myron has merely formulated a hypothesis.
He cannot draw any "conclusion" until he tests his hypothesis and demonstrates that similar outcomes consistently result from the same conditions. Testing his hypothesis may prove challenging, but unless he does so, he lacks a comprehensive theory.

In my view, while his hypothesis may indeed be valid, the most probable explanation for his experience is the recent physical strain from running to class. It’s crucial to note that I cannot convince anyone of this conclusion; my perspective is merely another hypothesis. Its validity holds no significance unless it undergoes testing.
6 0
14 days ago
How long does it take to raise the temperature of the air in a good-sized living room (3.00m×5.00m×8.00m) by 10.0∘C? Note that t
Softa [2035]
The required duration is 16.1 minutes. To determine the heat needed to raise the temperature, we must calculate the following amounts, where Q represents the required heat, m stands for mass, V represents the volume, C signifies specific heat, and ΔT indicates temperature change. After substituting the provided values into the formula and calculating, the next step is determining the required time based on the formula t = Q/P, where P is given as 1500 W. Ultimately, we find that the time needed is 16.1 minutes.
5 0
1 day ago
A metal, M, forms an oxide having the formula M2O3 containing 52.92% metal by mass. Determine the atomic weight in g/mole of the
ValentinkaMS [2425]

Answer:

The molar mass of the metal in grams per mole is calculated to be 8.87.

Explanation:

Initially, we can consider a sample of the compound weighing 100 g. This results in:

  • 52.92% metal: 52.92 g M
  • 47.80% oxygen: 47.80 g O

 By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

moles of oxygen=\frac{47.8g*1mol}{16g}

moles of oxygen=2.9875

The formula for the metal oxide indicates that:

2 M⁺³ + 3 O²⁻ ⇒ M₂O₃

From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

2.9875 moles of oxygen*\frac{2 moles of metal M}{1 mol of oxygen} = 5.975 moles of metal M

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass=\frac{52.92 g}{5.975 mol}

molar mass≅ 8.87 g/mol

The molar mass of the metal in grams per mole is 8.87.

The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.

3 0
6 days ago
Tiana jogs 1.5 km along a straight path and then turns and jogs 2.4 km in the opposite direction. She then turns back and jogs 0
inna [2210]

Answer:

Distance: 4.6 km Displacement= -0.2 km

Explanation:

The overall distance covered: 1.5 + 2.4 + 0.7 = 4.6 km

Displacement calculation: 1.5 - 2.4 + 0.7 = -0.2 km

The displacement could also simply be stated as 0.2 km depending on whether negative value is preferred.

7 0
14 days ago
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