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Alexxx
3 months ago
7

A 2.00x10^6 hertz radio signal is sent a distance of 7.30x10^10 meters from earth to a spaceship orbiting Mars. How much time do

es it take for the radio signal to travel from earth to the spaceship
Physics
1 answer:
Sav [3.1K]3 months ago
5 0
It requires  2.43\times 10^2  for a radio signal to journey from Earth to the spacecraft.
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Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
serg [3582]

Answer:

b) TA = TB = TC

Explanation:

  • When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
  • During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
  • The equilibrium state will be established once this equation is satisfied:

       \Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )

  • Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
  • When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
  • Therefore, option b) is correct.
8 0
3 months ago
Question 1
Keith_Richards [3271]

Answer:

1)  g = 4π² / m, 3) on the x-axis we have the pendulum lengths, while the y-axis shows the squared periods.

Explanation:

a) learners can model this system as a simple pendulum, where the angular velocity is given by

         w = √ g / l

Here, angular velocity, frequency, and period are interconnected:

         w = 2π f = 2π / T

Substituting yields:

         T = 2π√ l / g

Using this formula, students can calculate the gravitational acceleration by measuring the period for several pendulum lengths and plotting:

        T² = 4π²  l / g

We plot T² against l.

This represents a linear equation where T² is on the y-axis and l is on the x-axis:

        y = (4π² / g) l

The slope is given by:

         m = 4π² / g

Solving for g gives:

         g = 4π² / m

The slope is determined from the line's values rather than experimental data.

2) To perform the experiment, the string is secured to the sphere, then the pendulum length from the pivot to the sphere's center is measured using a tape measure. A slight angle (less than 10 degrees) is released, allowing the first swing to occur. Generally, the time for several oscillations, usually 10 or 20, is tracked to find the period:

    T = t / n

Next, a table is created comparing T² to the length, plotted with length on the x-axis to find the slope, from which the gravitational acceleration is derived.

3) The independent variable, which is the length of the pendulums, is plotted on the x-axis, while the dependent variable, the squared period, is on the y-axis.

4) Referring to the line equation:

            m = 4π² / g

             resulting in:

            g = 4π² / m

5) Once the spring is cut, the sphere continues to be influenced by gravitational acceleration. The harmonic motion ceases, and the sphere moves vertically.

5 0
4 months ago
Irene was investigating the behavior of gases at certain conditions. Which would most likely cause an increase in the rate of co
Yuliya22 [3333]
An increase in temperature and an increase in pressure can lead to a rise in the frequency of collisions. This can occur in several ways: first, the speed of gas molecules can be enhanced by raising their temperature, which directly affects their kinetic energy, allowing them to collide more often due to increased velocity. Secondly, if the container's size decreases, gas molecules will have less room to navigate and will therefore collide more frequently with the container's walls, increasing pressure, similar to what occurs in a piston-cylinder system.
6 0
2 months ago
A well-greased, essentially frictionless, metal bowl has the shape of a hemisphere of radius 0.150 m. You place a pat of butter
ValentinkaMS [3465]
Since there is no friction in the bowl, the total mechanical energy remains constant. Thus, we can conclude that the initial potential energy of the butter is equal to its final kinetic energy at the bowl's bottom, allowing us to calculate the speed v.
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