Response:
The speed at which the distance from the helicopter to you is changing (in ft/s) after 5 seconds is 
ft/ sec
Clarification:
Provided:
h(t) = 25 ft/sec
x(t) = 10 ft/ sec
h(5) = 25 ft/sec. 5 = 125 ft
x(5) = 10 ft/sec. 5 = 50 ft
At this point, we can determine the distance between the individual and the helicopter utilizing the Pythagorean theorem
Now, let's calculate the derivative of distance in relation to time
By plugging in the values for h(t) and x(t) and simplifying, we arrive at,
= 
= ft / sec
Answer:
Responses to the 3.17 punchline varied among many individuals, with some suggesting that it was a "full" moon day which prevented the astronauts from landing.
Others claimed that the astronauts took off during daylight hours when the moon was not visible. There were also comments that indicated that 'astro' refers to stars rather than satellites, explaining why they did not land.
A few even noted that 'astro naut' sounds like 'naught,' meaning zero (0), as a possible reason for their failure to land.
A bathroom scale operates under gravitational influence. Typically, a reading is captured when your body applies force onto the scale. Yet in this scenario, as both you and the scale move downwards, your body ceases to press against the scale. Consequently, the result is:
<span>The scale reading will instantly drop to zero</span>
Response:
length = 2L, mass = M/2, and maximum angular displacement = 1 degree
Clarification:
We examine only small amplitude oscillations (as in this scenario), which keeps the angle θ sufficiently small. In such situations, it's important to note that the pendulum's motion can be described by the equation:
The resulting solution is:
Here, 
represents the angular frequency of the oscillations, enabling us to find the period:
As a result, the period of a pendulum is determined solely by its length and is independent of both its mass and angle, provided the angle remains small. Therefore, the choice with the longest length gives the longest period.
Answer:
1.5 × 10³⁶ light-years
Explanation:
A particular square area in interstellar space measures roughly 2.4 × 10⁷² (light-years)². To find the area of a square, the following formula is utilized:
A = l²
where,
A represents the area of the square
l denotes the length of one side of the square
Thus, l = √A = √2.4 × 10⁷² (light-years)² = 1.5 × 10³⁶ light-years
