Answer:
H+(aq) + OH-(aq) ⟶ H2O(l)
Explanation:
Step 1: The balanced equation can be presented as
HCN(aq) + KOH(aq) ⟶ H2O(l) + KCN(aq)
H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶ H2O(l) + K+(aq) + CN-(aq)
Step 2: The net ionic equation is formed by removing the spectator ions — those that appear on both sides of the equation — leading us to the final representation:
H+(aq) + OH-(aq) ⟶ H2O(l)
Answer:The pH measured 10 cm from the most acidic end is 3.42.
Explanation:
The pH at one end = 1The pH at the other end = 13
The chamber length = 13 cm
The change in pH concerning the chamber's length from the acidic end is
Thus, the pH at a distance of 10 cm from the most acidic end is 3.42.
Response:

Clarification:
Hello,
In this scenario, since a single drop equates to 0.05 mL of the solution provided, with a concentration of 0.02 g/mL, the mass of oleic acid in one drop calculates to:

Best wishes.
Hello, in this situation, the chemical reaction occurring is as follows: Next, we will ascertain the limiting reactant by calculating the moles of magnesium oxide produced from 3.86 g of magnesium and 155 mL of oxygen using the given mole ratios of 2:1:2 and applying the ideal gas equation, demonstrating that oxygen is the limiting reactant because it generates the least magnesium oxide. Subsequently, we determine the mass of magnesium consumed solely by the oxygen.
The appropriate answer is option E. Gibbs free energy can be expressed using the equation: ΔG = ΔH - TΔS, where ΔH denotes the change in enthalpy of the reaction, T is the reaction temperature, and ΔS signifies entropy change. For our calculations, we have ΔH = -720.5 kJ/mol which converts to -720500 J/mol (given that 1 kJ = 1000 J), ΔS = -263.7 J/K, and T = 141.0°C, which equals 414.15 K. Consequently, the Gibbs free energy for the specified reaction at 141.0°C is calculated as -611.3 kJ/mol.