The mixture’s density is 1.57 g/cm³.
Step 1: Determine the mass of the butter.
Step 2: Determine the mass of the sand.
Step 3: Determine the density of the mixture.
Total mass = 0.860 g + 2.28 g = 3.14 g.
Total volume = 1 cm³ + 1 cm³ = 2 cm³
Answer: The process of heating a crucible to eliminate moisture from a hydrate.
Explanation:
The available choices are:
a. Heating a solvent to aid in the dissolution of a solute.
b. Heating a solid in isolation to remove moisture.
c. Bringing water to a boil for use in a water bath.
d. Heating a crucible to eliminate moisture from a hydrate.
Possible actions that can be done on a hot plate include:
a. Heating a solvent to assist a solute in dissolving.
b. Heating a solid in isolation to dry it.
c. Heating water to boiling for a water bath.
However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.
Consequently, the correct procedure is heating a crucible to remove water from a hydrate.
Consequently, she feels very anxious because she has 345600 seconds to wait. Explanation: 60 seconds make up 1 minute, and 60 minutes constitute an hour. Each hour has 3600 seconds (60*60) and 24 hours make up a day. Hence, 3600 seconds multiplied by 24 hours results in 1 day equating to 86400 seconds—therefore, over four days, we have 86400 * 4 equating to 345600.
Answer:
Explanation:
Considering the reaction: 2X + 3Y = 3Z, combining 2.00 moles of X with 2.00 moles of Y results in the production of 1.75 moles of Z.
2 mol 2 mol 1.75 mol
2X + 3Y = 3Z
2 mol is required with 3 mol to yield 3 mol.
3 mol Z / 3 mol Y = 1 to 1
should yield 2 mol Z
1.75 / 2 = 87.5 % production yield
Answer:
78.96 g of NaC2H3O2
Explanation:
The following information is provided:
- The solution's volume is 350 mL
- The solution's molarity is 2.75 M
- The molar mass of NaC2H3O2 is 82.04 g/mol
We need to find the mass of the solute:
First, we calculate the number of moles:
Moles = Molarity × Volume
Thus;
Moles of solute = 2.75 M × 0.350 L
= 0.9625 moles
Next, we find the mass:
Mass = Moles × Molar mass
= 0.9625 moles × 82.04 g/mol
= 78.9635 g
= 78.96 g
Therefore, the amount of NaC2H3O2 required is 78.96 g
