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vagabundo
3 days ago
13

65g of nitric acid are produced in a reaction. 2.5g of platinum are added to the reaction vessel at the start of the reaction to

act as a catalyst. How much platinum will there be left in the vessel at the end of the reaction?
Chemistry
1 answer:
alisha [964]3 days ago
6 0

Answer:

2.5 g of platinum

Explanation:

A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.

Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.

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An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decompo
lions [985]

Answer:

The rate law for the decomposition reaction is:

R=k[D]^2

The unit for the rate constant will be M^{-1}s^{-1}

Explanation:

D\rightarrow Product

The rate law can be expressed as:

R=k[D]^x..[1]

When the drug concentration is tripled, the decomposition rate rises by a factor of nine.

[D]'=3[D]

R'=9\times R

R'=k[D]'^x...[2]

[1] ÷ [2]

\frac{R}{R'}=\frac{k[D]^x}{k[D']^x}

\frac{R}{9R}=\frac{k[D]^x}{k[3D]^x}

9=3^x

Solving for x results in:

x = 2.

This indicates a second-order reaction.

The decomposition reaction's rate law is:

R=k[D]^2

The unit for the rate constant will be:

k=\frac{R}{[D]^2}=\frac{M/s}{(M)^2}=M^{-1}s^{-1}

The unit for the rate constant will be M^{-1}s^{-1}.

5 0
12 hours ago
A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
castortr0y [923]

Answer:

The forward reaction will keep occurring until all NO or all NO₂ is consumed.

Clarification:

  • According to Le Châtelier's principle, when a system at equilibrium experiences a disturbance from an outside source, the system will adjust to counteract this disturbance and restore equilibrium.

  • Thus, removing the product (N₂O₃) from the system effectively lowers the product concentration, prompting the reaction to shift forward and generate additional product in order to alleviate the strain caused by the removal of N₂O₃.

  • Consequently, the reaction will proceed forward until all of either NO or NO₂ is depleted.

5 0
2 days ago
A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
KiRa [971]

Answer:

There are 5.5668 moles of water for every mole of CuSO₄.

Explanation:

The mass of anhydrous CuSO₄ is:

23.403g - 22.652g = 0.751g.

mass of crucible + lid + CuSO₄ - mass of crucible + lid

Given that the molar mass of CuSO₄ is 159.609g/mol, we calculate the moles:

0.751g ×\frac{1mol}{159,609g} = 4.7052x10⁻³ moles CuSO₄

The mass of water in the initial sample is:

23.875g - 0.751g - 22.652g = 0.472g.

mass of crucible + lid + CuSO₄ hydrate - CuSO₄ - mass of crucible + lid

As the molar mass of H₂O is 18.02g/mol, we find the moles:

0.472g ×\frac{1mol}{18,02g} = 2.6193x10⁻² moles H₂O

The mole ratio of H₂O to CuSO₄ is:

2.6193x10⁻² moles H₂O / 4.7052x10⁻³ moles CuSO₄ = 5.5668

This indicates there are 5.5668 moles of water per mole of CuSO₄.

I hope this is helpful!

5 0
8 days ago
he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
eduard [944]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2. 5.6\cdot 10^{13} electrons per individual

Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

v_d=\frac{I}{neA}

where

I stands for current

n represents the density of free electrons

e=1.6\cdot 10^{-19}C indicates the charge of an electron

A signifies the wire's cross-sectional area

The wire's cross-sectional area can be determined as

A=\pi r^2

where r denotes the wire's radius. Thus, the equation transforms to

v_d=\frac{I}{ne\pi r^2}

In this scenario, we have:

I = 8.0 A as the current

8.5\cdot 10^{28} m^{-3} indicates the free electron concentration

d = 1.5 mm is the diameter, making the radius

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

So, the resulting drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The entire length of the cord is

L = 3.00 m

And the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Consequently, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, thus the total electrons in this cord would be

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

Overall, the Earth's population rounds to 8 billion individuals, equating to

N'=8\cdot 10^9

Hence, the number of electrons distributed to each person is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
5 days ago
Yasir wants to determine if there is a relationship between room color and sleep. Based on his research, Yasir makes an educated
Tems11 [846]

Yasir wished to explore how sleep relates to room color. He conducted necessary preliminary research and formed a hypothesis suggesting individuals doze off faster in blue-painted rooms compared to those painted in yellow. Yasir surveyed several individuals about their color preference—yellow or blue—and utilized their feedback to assess the validity of his hypothesis. However, he did not conduct an actual experiment to examine the impact of room color on sleep, and he failed to clearly define the variables that should have been part of his experiment.

Hence, the correct answer would be,

An experiment that directly tests the hypothesis

Variables to be tested by an experiment

3 0
6 days ago
Read 2 more answers
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