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Dmitrij
3 months ago
8

While running these tests, crall notices a similarity in the velocity measured at the ground independent of whether the tennis b

all is thrown upward or downward. she decides to see if her hypothesis that the final speed is independent of the sign of the initial velocity is correct. crall and whipple decide to run the experiment several times using different initial speeds of the elevator each time comparing the final velocity of the tennis ball when the elevator is traveling upward vs. downward at the same speed?
Physics
2 answers:
kicyunya [3.2K]3 months ago
6 0

When the ball reaches the ground, it will consistently possess velocity directed along the force of gravity. Assuming upward motion is classified as positive, then it will always have a negative velocity upon hitting the ground because if it was initially thrown upwards, gravity will reduce its speed, resulting in a negative terminal velocity. Conversely, if it begins falling with an initial downward velocity, gravity will further accelerate the ball in that same downward direction, retaining a negative velocity. However, the final magnitude will differ in each scenario. The ball will achieve a higher final speed upon impact if the elevator descends.

Keith_Richards [3.2K]3 months ago
6 0

Answer:

The final speeds will vary.

Explanation:

Rationalizing the situation:

Downward motion experiences similar dynamics due to gravitational influences. In a vacuum, an object's terminal velocity remains consistent.

When projecting the ball downward, potential energy transforms into kinetic energy. However, launching it upwards demands more energy to counteract gravity's force. Consequently, the resulting speeds of the ball differ.

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In concave mirror, the size of image depends upon
Maru [3345]

Answer:

The positioning of the object along the principal axis relative to the concave mirror.

Explanation:

In a concave mirror, the characteristics of the image generated depend on where the object is situated in relation to the mirror. The distance from the mirror to the object positioned along the principal axis is key.

The nearer the object is to the mirror, the larger or more magnified the image will appear. For example, placing an object between the focal point and the concave mirror's pole results in a significantly larger image compared to an object placed outside the center of curvature of the mirror.

8 0
3 months ago
Read 2 more answers
You are working as an assistant to an air-traffic controller at the local airport, from which small airplanes take off and land.
serg [3582]

Answer:

d = 2021.6 km

Explanation:

This distance problem can be solved using vector analysis; it's best to find each plane's position components before applying the Pythagorean theorem to calculate the separation between them.

For Airplane 1:

Height   y₁ = 800m

Angle θ = 25°

           cos 25 = x / r

           sin 25 = z / r

           x₁ = r cos 20

           z₁ = r sin 25

          x₁ = 18 103 cos 25 = 16,314 103 m = 16314 m

          z₁ = 18 103 sin 25 = 7,607 103 m = 7607 m

For Plane 2:

Height   y₂ = 1100 m

Angle θ = 20°

          x₂ = 20 103 cos 25 = 18.126 103 m = 18126 m

          z₂ = 20 103 sin 25 = 8.452 103 m = 8452 m

To determine the distance between the planes using the Pythagorean theorem:

         d² = (x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²2

Now, we perform the calculations:

        d² = (18126-16314)²  + (1100-800)² + (8452-7607)²

        d² = 3,283 106 + 9 104 + 7,140 105

        d² = (328.3 + 9 + 71.40) 10⁴

        d = √(408.7 10⁴)

        d = 20,216 10² m

        d = 2021.6 km

7 0
3 months ago
The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0
kicyunya [3294]
To solve this problem, Coulomb's law will be applied as follows:
F = k*q1*q2 / r^2 where:
F indicates the force magnitude between the charges
k is a constant = 9.00 * 10^9 N.m^2/C^2
q1 = <span>+2.4 × 10–8 C
q2 = </span><span>+1.8 × 10–6 C
r represents the distance separating the charges = </span><span>0.008 m

By substituting these values, we derive:
F = (9*10^9)(2.4*10^-8)(1.8*10^-6) / (0.008)^2 = 6.075, which rounds to 6.1 Newtons

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8 0
3 months ago
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