Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.
Explanation:
Let Q be the speed of the boat, and P be the speed of the river flow.
R represents the resultant velocity combining boat velocity and river current.
According to vector addition using the law of triangles:

From the diagram:
P = 3.5 km/h, Q = 4.5 km/h




Therefore, her velocity magnitude relative to the shore is 5.70 km/h.
Respuesta:
Explicación:
Al analizar esta pregunta, considera el movimiento circular. Primero, determina la máxima fuerza que puede aplicarse al hilo. F = mg, entonces F = (10)(10) = 100 N. Luego, calcula la aceleración centrípeta de la masa de 0.5 kg, a = F/m, así que a = 100/.5 = 200 m/s². En la hoja de ecuaciones, usa la fórmula a (aceleración centrípeta) = v²/r, por lo que 200 = v²/2; por consiguiente, v = 20 m/s. ¡Espero que esto sea útil!
Answer:3.87*10^-4
Explanation:
To determine the mass reduction, delta mass Xe, of the xenon nucleus due to its decay, we first use the provided wavelength of the gamma radiation to calculate its frequency via c = freq*wavelength.
From C=f*lambda we set up: 3*10^8=f*3.44*10^-12.
Solving gives frequency F=0.87*10^20 Hz.
Next, we calculate the emitted energy using the equation E=hf, which translates to E=f*Planck's constant.
Thus, E=0.87*10^20*6.62*10^-34, resulting in E=575.94*10^(-16).
This energy is then converted from joules to MeV.
Utilizing the formula E=mc^2, with c^2 = 931.5 MeV/u, enables us to find the reduction in mass, yielding
3.87*10^-4 u.
Answer:
(a) 16.777 miles
(b) Yes, he exceeded the speed limit
Explanation:
(a)
We need to perform the necessary calculations to convert kilometers to miles:

Thus, the distance of the trip in miles is:

(b)
Next, we will compute the man's speed during the journey:

Before that, we must convert minutes to hours:

The resulting speed is:

Consequently:

Thus, it can be concluded that the driver was speeding
Answer:
2.45 m
Explanation:
To begin, we need to determine the book's time of flight, utilizing the equation for vertical motion:

with
h = 1.19 m representing the height traveled by the book
g = 9.8 m/s^2 being the gravitational acceleration
t symbolizing the time of flight
By solving for t,

Next, we calculate the horizontal distance the book travels, defined by

where
denotes the horizontal velocity
t = 0.49 s being the time of flight
By substituting,

Thus, the book lands at a distance of 2.45 m.