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hjlf
4 months ago
7

A solution with 117 grams of lithium hydroxide and another with 141 grams of hydrogen bromide are combined. They react according

to this equation: LiOH + HBr → LiBr + H2O. What is the theoretical yield of lithium bromide? Use the periodic table and polyatomic ion resource. A. 117 g B. 141 g C. 151 g D. 258 g E. 424 g
Chemistry
1 answer:
Tems11 [2.7K]4 months ago
4 0

Answer: C. 151 g

Solution: The balanced equation given is:

LiOH+HBr\rightarrow LiBr+H_2O

From this equation, the ratio of moles between all substances is 1:1. We have 117 grams of LIOH and 141 grams of HBr available and need to calculate the theoretical yield of LiBr.

We should convert each reactant’s grams into moles to identify the limiting reagent since the theoretical yield relies on it.

Molar mass for LiOH = 6.94 + 15.999 + 1.008 = 23.947 grams per mole

Molar mass for HBr = 1.008 + 79.904 = 80.912 grams per mole

To find the moles of each reactant, we divide their grams by their respective molar masses.

Moles of LiOH = 117gLiOH(\frac{1mol}{23.947}) = 4.89 mol

Moles of HBr = 141gHBr(\frac{1mol}{80.912g}) = 1.74 mol

As there are fewer moles of HBr, it is the limiting reactant. With a 1:1 mol ratio between HBr and LiBr, 1.74 moles of LiBr can be produced.

Molar mass of LiBr = 6.94 + 79.904 = 86.844 grams per mole

The mass of LiBr formed = 1.74molLiBr(\frac{86.844g}{1mol}) = 151 g LiBr

Based on calculations, the theoretical yield of LiBr is 151 g, hence the correct answer is C.


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