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Travka
2 months ago
11

A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?

CH C2H2 C6H6 C6H
Chemistry
2 answers:
KiRa [2.9K]2 months ago
5 0

A compound sample comprises 60.0 g of carbon and 5.05 g of hydrogen.

To find the molar ratio, divide by the molar masses of carbon (12) and hydrogen (1).

For carbon: 60/12=5 and for hydrogen: 5.05/1=5.009

This results in a ratio of C:H=5:5, which simplifies to 1:1.

The overall molar mass is 78.

To determine the molecular formula, divide the molar mass by the sum of the atomic masses of carbon and hydrogen: 78/(12+1)=78/13=6.

Thus, the compound is C6H6.


KiRa [2.9K]2 months ago
3 0
Step 1: Determine Moles for Each Element:

Moles of C = 60.0 / 12 = 5

Moles of H = 5.05 / 1.008 = 5.009

Step 2: Calculate Mole Ratio:
Divide each mole number by the smallest mole count.

H: C

5.009/5: 5/5

This simplifies to 1: 1
Thus,
Empirical Formula = C₁H₁ or CnHn ------ (1)

Step 3: Determine the Molecular Formula:
Using the formula,
n = Molecular Mass / Empirical Formula Mass

Molecular Mass = 78.12 g/mol

Empirical Formula Mass = 12 + 1 = 13, thus C = 12 & H = 1
Therefore,
n = 78.12 / 13

n = 6

Substituting n in equation 1,

C₆H₆
Result:
The correct molecular formula is C₆H₆.
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Explanation:

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  • Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.
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