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KengaRu
2 months ago
13

A rock falls for 1.43 seconds how far did it fall? The falls's velocity is an acceleration of -9.81 m/s2

Physics
1 answer:
Ostrovityanka [3.2K]2 months ago
7 0

Answer:

s = -0.100 \  m

Explanation:

From kinematic equations, we derive that

s = ut + \frac{1}{2}gt^2

In this case, u denotes the rock's initial velocity, which is  0 m/s, as there was no indication that it was in motion prior to falling.

By substituting 1.43 s for t and using -9.8m/s^2 for g, we arrive at

s = 0 *1.43 + \frac{1}{2}(-9.8)*(0.143)^2

=>     s = -0.100 \  m

The negative value indicates that the movement is directed toward the negative y-axis.

 

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A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Igno
Ostrovityanka [3204]

Answer

Given data:

height of the dam = 15 m

effective area for water flow = 2.3 x 10⁻³ m²

Applying the principle of energy conservation:

m g h = \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v= \sqrt{2\times 9.8 \times 15}

v= \sqrt{294}

v = 17.15 m/s

water discharge

Q = A V

Q = 2.3 x 10⁻³ x 17.15

Q = 0.039 m³/s

3 0
2 months ago
A woman living in a third-story apartment is moving out. Rather than carrying everything down the stairs, she decides to pack he
inna [3103]
Let T be the force exerted on the rope by her. This force induces tension in the rope, which exerts an upward force on the crates, while the weight of the crate pulls downward. Thus, the net force acting on the crate can be expressed as mg - T, acting in the downward direction. According to Newton's law, we can set up the equation: mg - T = ma. Given that a = 0 (the speed remains constant), this simplifies our equation to mg - T = 0, which leads to T = mg. Therefore, T = 25 x 9.8 = 245 N, indicating that the force she needs to apply is 245 N.
5 0
1 month ago
If Pete ( mass=90.0kg) weights himself and finds that he weighs 30.0 pounds, how far away from the surface of the earth is he
serg [3582]
The answer is 9938.8 km. Explanation: 1 pound-force = 4.48 N. Hence, 30.0 pounds-force = 134.4 N. The gravitational force between Earth and an object on its surface is defined by: Where M denotes Earth’s mass, m is the object's mass, and R represents the Earth's radius (6371 km). To determine height (h) above Earth's surface, we compare ratios. Ultimately, Pete's weight would be 30 pounds at a height of 9938.8 km from the Earth's surface.
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1 month ago
a hippopotamus produces a pressure of 250000 pa when it is standing on all four feet if the weight of the hippo is 40000 N what
Maru [3345]

0.04m²

Explanation:

Known values:

Pressure = 250000Pa

Weight = 40000N

Unknown:

Area of each foot =?

Solution:

Pressure is defined as the force applied per unit area of an object

  Pressure = \frac{force}{area}

To determine the area;

        Area = \frac{force }{pressure}

    Area = \frac{40000}{250000} = 0.16m²

The force exerted by all four feet amounts to 0.16m²

thus, the area for each foot is \frac{0.16}{4} = 0.04m²

Learn more:

Pressure

8 0
1 month ago
A hot air balloon of total mass M (including passengers and luggage) is moving with a downward acceleration of magnitude a. As i
inna [3103]

Answer:

The ratio of mass that is discarded is determined by this equation:

M - m = (3a/2)/(g²- (a²/2) - (ag/2))

Explanation:

The force acting on an object in motion is defined by the equation:

F = ma

Additionally, there is a gravitational force consistently acting downwards on the object, defined as g = 9.8 ms⁻²

For convenience, we will utilize a positive notation for downward acceleration and a negative notation for upward acceleration.

Case 1:

The hot air balloon has mass = M

Acceleration = a

Upward thrust from hot air = F = constant

Gravitational force acting downward = Mg

The net force on the balloon can be expressed as:

Ma = Gravitational force - Upward Force                              

Ma = Mg - F                      (since the balloon moves downward, that means Mg > F)

F = Mg - Ma

F = M (g-a)

M = F/(g-a)

Case 2:

After releasing the ballast, the new mass becomes m. The new upward acceleration is -a/2:

The net force is expressed as:

-m(a/2) = mg - F        (The balloon is moving upwards, hence F > mg)

F = mg + m(a/2)

F = m(g + (a/2))

m = F/(g + (a/2))

Determining the fraction of the mass initially dropped:

M-m = \frac{F}{g-a} - \frac{F}{g+\frac{a}{2} }\\M-m = F*[\frac{1}{g-a} - \frac{1}{g+\frac{a}{2} }]\\M-m = F*[\frac{(g+(a/2)) - (g-a)}{(g-a)(g+(a/2))} ]\\M-m = F*[\frac{g+(a/2) - g + a)}{(g-a)(g+(a/2))} ]\\M-m = F*[\frac{(3a/2)}{g^{2}-\frac{a^{2}}{2}-\frac{ag}{2}} ]

5 0
2 months ago
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