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15 days ago

A rock falls for 1.43 seconds how far did it fall? The falls's velocity is an acceleration of -9.81 m/s2

Physics

1 answer:

Ostrovityanka [942]15 days ago

7 0

Answer:

$s = -0.100 \ m$

Explanation:

From kinematic equations, we derive that

$s = ut + \frac{1}{2}gt^2$

In this case, u denotes the rock's initial velocity, which is 0 m/s, as there was no indication that it was in motion prior to falling.

By substituting 1.43 s for t and using $-9.8m/s^2$ for g, we arrive at

$s = 0 *1.43 + \frac{1}{2}(-9.8)*(0.143)^2$

=> $s = -0.100 \ m$

The negative value indicates that the movement is directed toward the negative y-axis.

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Answer:

Explanation:

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Secondly, Newton's law of universal gravitation defines the force between two masses: Fg = mMG/r², where Fg denotes gravitational force, m and M signify the masses, G represents the gravitational constant, and r indicates the distance separating the two masses.

Thus:

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ME = PE + KE = 3/2 mMG/r

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13 days ago

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9 days ago

Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st

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Answer:

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<pInitially, for the three spheres, we have:

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7 days ago

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Answer:

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5 days ago

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