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lidiya
12 days ago
15

A car travels north at 30 m/s for one half hour. It then travels south at 40 m/s for 15 minutes. The total distance the car has

traveled and its displacement are: Group of answer choices 36 km; 36 km N. 90 km; 18 km N. 90 km; 36 km N. 36 km; 36 km S. 18 km; 18 km S.
Physics
1 answer:
serg [2.5K]12 days ago
5 0

Answer:

xtotal = 90km

displacement = 18km N

Explanation:

To determine how far the car has traveled in total, you start by calculating the distance it covers while going north. The formula used for this is:

x=vt    (1)

x: distance

v: speed of the car = 30 m/s

t: time = half an hour

To compute the distance, you need to convert the time from hours into seconds:

t=0.5\ h*\frac{3600s}{1\ h}=1800s

Afterward, substitute the values of t and v into equation (1):

x=(30m/s)(1800s)=54000m     (2)

Next, calculate the distance covered by the car when traveling south:

x'=v't'\\\\v'=40\frac{m}{s}\\\\t'=15\ min

You need to change the time from minutes to seconds:

t'=15\ min*\frac{60s}{1min}=900s

x'=(40m/s)(900s)=36000m

In the end, combine both distances x and x':

x_{total}=x+x'=54000m+36000m=90000m=90km

The car has covered a total distance of 90km

As for total displacement, this represents the distance from the car's final position back to its starting point. It is found by subtracting x' from x:

d=x-x'=54000m-36000m=18000m=18km

The total displacement amounts to 18km towards the north from the car's original position.

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answer:

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19 days ago
For a projectile, which of the following quantities are constant during the flight: x, y, vx, vy, v, ax, ay? Check all that appl
Yuliya22 [2420]

Response:

C. vx

F. ax

G. ay

Clarification:

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Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.

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28 days ago
THE RELATIVE ANGLE AT THE KNEE CHANGES FROM 0O TO 85O DURING THE KNEE FLEXION PHASE OF A SQUAT EXERCISE. IF 10 COMPLETE SQUATS A
ValentinkaMS [2425]

Answer: total angular distance = 1700° and 29.7 rad

   the total angular displacement = 0

Explanation:

This is a breakdown of the calculations needed.

The task is to determine both the total angular distance and displacement experienced by the knee.

To calculate the distance traveled by the knee, consider that when squatting, the knee bends 85° to lower, and then another 85° to return to standing (upright). Thus, the cumulative angular movement during the squat totals 170°.

For 10 squats, the knee must undergo 170° motion multiplied by 10, resulting in:

10 * 170° = 1700°

As such, the total angular distance reached is 1700°.

Now converting this to radians since both degree and radian outputs are required:

Since 2π equals 360°, it follows that one degree equates to about 57.3°;

∅ (rad) = ∅ (deg) * 2π/360°

∅ (rad) = 1700° * 2π/360° = 29.7 rad

∅ (rad) = 29.7 rad

For the second part, remember that angular displacement is determined by the angular distance divided by time, leading to a displacement of zero because the knee's ending position is the same as its starting position.

I hope this is helpful!!!!

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A proton moves along the x-axis with vx=1.0×107m/s. As it passes the origin, what are the strength and direction of the magnetic
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