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lidiya
3 months ago
15

A car travels north at 30 m/s for one half hour. It then travels south at 40 m/s for 15 minutes. The total distance the car has

traveled and its displacement are: Group of answer choices 36 km; 36 km N. 90 km; 18 km N. 90 km; 36 km N. 36 km; 36 km S. 18 km; 18 km S.
Physics
1 answer:
serg [3.5K]3 months ago
5 0

Answer:

xtotal = 90km

displacement = 18km N

Explanation:

To determine how far the car has traveled in total, you start by calculating the distance it covers while going north. The formula used for this is:

x=vt    (1)

x: distance

v: speed of the car = 30 m/s

t: time = half an hour

To compute the distance, you need to convert the time from hours into seconds:

t=0.5\ h*\frac{3600s}{1\ h}=1800s

Afterward, substitute the values of t and v into equation (1):

x=(30m/s)(1800s)=54000m     (2)

Next, calculate the distance covered by the car when traveling south:

x'=v't'\\\\v'=40\frac{m}{s}\\\\t'=15\ min

You need to change the time from minutes to seconds:

t'=15\ min*\frac{60s}{1min}=900s

x'=(40m/s)(900s)=36000m

In the end, combine both distances x and x':

x_{total}=x+x'=54000m+36000m=90000m=90km

The car has covered a total distance of 90km

As for total displacement, this represents the distance from the car's final position back to its starting point. It is found by subtracting x' from x:

d=x-x'=54000m-36000m=18000m=18km

The total displacement amounts to 18km towards the north from the car's original position.

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Answer:

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Explanation:

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Response:

45cm

Clarification:

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