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Alik
17 days ago
5

1. The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force th

at Earth exerts on the sun?(1 point)
Earth pulls the sun away from itself with a force equal to the ratio of the mass of the sun to the mass of Earth.

Earth pulls the sun away from itself with an equal force.

Earth pulls the sun toward itself with an equal force.

Earth pulls the sun toward itself with a force equal to the ratio of the mass of the sun to the mass of Earth.

2. Two rockets with the same mass are accelerated. Rocket A accelerates twice as quickly as rocket B. Which statement is correct?(1 point)

The motor in rocket A is twice as powerful as the motor in rocket B.

The motor in rocket A is four times as powerful as the motor in rocket B.

The motor in rocket A is half as powerful as the motor in rocket B.

The motor in rocket A is half as powerful as the motor in rocket B.

3. Five motorboats are being tested to see which reaches the highest velocity in the same amount of time. After graphing the acceleration versus force for each motorboat, the graph is a sloped line with a y-intercept of zero. Which statement is correct about these motorboats?(1 point)

All five motorboats have the same mass, which cannot be calculated from the graph.

All five motorboats have the same final velocity, which cannot be calculated from the graph.

All five motorboats have the same final velocity, which can be calculated from the graph.

All five motorboats have the same mass, which can be calculated from the graph.

4. Three objects are released to the ground while the mass and net force of each is recorded. Air resistance is assumed to be negligible. Which statement is correct about all three objects?(1 point)

No statements can be made about the objects without measuring the acceleration of each.

The ratio of mass to acceleration is constant across all objects.

The ratio of net force to acceleration is constant across all objects.

The ratio of net force to mass is constant across all objects.

5. A helicopter is accelerating up into the air while it is also accelerating due north. Which statement about the forces acting on the helicopter is true?(1 point)

The drag on the helicopter is directed downward and to the south.

The drag on the helicopter is directed upward and to the south.

The drag on the helicopter is directed downward and to the north.

The drag on the helicopter is directed upward and to the north.
Physics
2 answers:
Sav [2.2K]17 days ago
6 0

Answer:

1. The sun is moved away from the Earth by an equal force exerted by the Earth.

Keith_Richards [2.2K]17 days ago
6 0

Answer:

Rocket A possesses twice the power compared to Rocket B.

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A Federation starship (8.5 ✕ 106 kg) uses its tractor beam to pull a shuttlecraft (1.0 ✕ 104 kg) aboard from a distance of 14 km
Keith_Richards [2256]
Consider the diagram below.

m₁ = 8.5 x 10⁶ kg, the starship's mass
m₂ = 10⁴ kg, the shuttlecraft's mass
a₁ =  acceleration of the starship
a₂ = the acceleration of the shuttle
F = 4 x 10⁴ N, the force exerted

Let y represent the distance covered by the starship
Let x denote the distance covered by the shuttlecraft
If t indicates the travel time, then
y = 0.5a₁t²                  (1)
x = 0.5a₂t²                  (2)

F = m₁a₁ = m₂a₂         (3)
Additionally,
x + y = 14000 m          (4)

From (2), we derive
a₁ = (4 x 10⁴ N)/(8.5 x 10⁶ kg) = 4.706 x 10⁻³ m/s²
a₂ = (4 x 10⁴ N)/(10⁴ kg) = 4 m/s²

From (1), (2) and (4), we find
0.5*(t s)²*(4 + 4.706 x 10⁻³ m/s²) = 14000 m
2.002353t² = 14000
t² = 6991.774 s²
t = 83.617 s

Thus
x = 0.5*4*6991.774 = 13984 m = 13.984 km
y = 0.5*4.706 x 10⁻³*6991.774 = 16.452 m

The starship moves roughly 16.5 meters while towing the shuttlecraft by 13.98 kilometers.

Result: The starship shifts by 16.5 m (to the nearest tenth)

3 0
20 days ago
You throw a tennis ball (mass 0.0570 kg) vertically upward. It leaves your hand moving at 15.0 m/s. Air resistance cannot be neg
Sav [2226]
The answer is 195 J.
3 0
6 days ago
A proton has mass 1.7 ✕ 10−27 kg. what is the magnitude of the impulse required to increase its speed from 0.991c to 0.994c?
Maru [2355]

Impulse can be equated to the force associated with momentum change, expressed as F*t = mv - mu
Given the mass and speed values are provided, apply the formula from the right-hand side:
mass, m = 1.7 x 10^27 kg
initial velocity, u = 0.991 x (3 x 10^8) = 2.973 x 10^8
final velocity, v = 0.994 x (3 x 10^8) = 2.982 x 10^8
Consequently, the calculation is:
Impulse = mv - mu
= [(1.7 x 10^27) x (2.982 x 10^8)] - [(1.7 x 10^27) x (2.973 x 10^8)]
= (5.0694 x 10^35) - (5.0694 x 10^35)
= 0

6 0
29 days ago
A beaker containing mercury is placed inside a vacuum chamber in a laboratory. the pressure at the bottom of the beaker is 26000
inna [2205]
The density of mercury in its liquid form is
\rho = 13.5 g/cm^3=13500 kg/m^3

We understand that the equation determining the pressure at the base of a fluid column can be expressed through Stevin's law
p=\rho g h
where
\rho represents the density of the liquid
g signifies the acceleration due to gravity
h indicates the height of the fluid column

Given that the pressure at the lower section of the beaker is p=26000 Pa, we can manipulate the preceding formula to calculate the height of the mercury column
h= \frac{p}{\rho g}= \frac{26000 Pa}{(13500 kg/m^3)(9.81 m/s^2)}=0.196m = 19.6 cm
5 0
21 day ago
What was the vertical component of her acceleration during push-off? the positive direction is upward?
Maru [2355]
<span>The solutions to these two equations are: A) a = (F-W)/m = (100-500)/500/g = 9.8*500/500 = +9.8 m/sec^2 B) a1 = +9.8-g = 0</span>
5 0
17 days ago
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