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ANEK
1 month ago
7

Subsurface ocean currents continually circulate from the warm waters near the equator to the colder waters in other parts of the

world. What is the main cause of these currents?
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
8 0
<span>The primary factor behind these currents is the </span>variability in the density of ocean waters.
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This image shows the direction of the flow of water through a constricted pipe. Which of the following happens as you move from
Keith_Richards [3271]
C. The rate of water flow diminishes.
6 0
2 months ago
(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i
kicyunya [3294]

Response:

a) P = 370.993\,kPa, b) F = 25.948\,kN

Clarification:

a) The absolute pressure at a depth of 27.5 meters is:

P = P_{atm} + P_{man}

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (27.5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

P = 370.993\,kPa

b) The force applied by the water is:

F = (P - P_{atm})\cdot A

F = (370.993\,kPa-101.3\,kPa)\cdot \left(\frac{\pi}{4} \right)\cdot (0.35\,m)^{2}

F = 25.948\,kN

5 0
2 months ago
Read 2 more answers
Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h
Yuliya22 [3333]

I disagree

Justification:

Fluorescent substances will emit light when exposed to ultraviolet light because the UV radiation excites their molecules.

Microwaves generate micro-waves from a different wavelength spectrum and will not excite the molecules to fluoresce

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3 0
2 months ago
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15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
Keith_Richards [3271]

Answer:

Explanation:

Considering that,

The mass of the first vehicle

M1= 328kg

It is traveling in the positive x direction at a speed of

U1 = 19.1m/s

The speed of the second vehicle

U2 = 13m/s, moving in the same direction as the first vehicle..

The mass of the second vehicle

M2 = 790kg

The speed of the second vehicle post-collision

V2 = 15.1 m/s

The speed of the first vehicle following the collision

V1 =?

This represents an elastic collision,

and applying the principle of conservation of momentum

The momentum prior to the collision must equal the momentum afterwards

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

V1 = 14.04 m/s

The speed of the first vehicle after the collision is 14.04 m/s

5 0
2 months ago
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